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Marina CMI [18]
3 years ago
11

I need help and show the work?

Mathematics
1 answer:
ki77a [65]3 years ago
5 0
The difference is the answer to a subtraction problem. 

<span>Subtract the smaller insect (1.33) from the bigger insect (2.01), which would end up looking like this: </span>

<span>2.01 cm </span>
<span>-1.33 cm </span>
<span>-------- </span>
<span>0.68 cm </span>

<span>So, the difference of the subtraction problem is 0.68 cm.</span>
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What is the area of a circular wrestling region with a 42 ft diameter
zloy xaker [14]

Answer:

The area of a circular wrestling region with a 42 fr diameter is

A≈1385.44ft²

4 0
4 years ago
How can i Multiply. ×2/7*3/5
lys-0071 [83]
<span><span>2/7 times 2 by 5 and times 7 by 5 also then that would equal 10/35
then you times 3 by 7 and times 5 by 7 to get 21/35 then add 10 and 21 to get 31 then it will be 31/35 then try to reduce it but u cant so the answer is 31/35</span></span>
8 0
3 years ago
Read 2 more answers
(t-distribution) A manufacturing firm claims that the batteries used in laptop computers will last an average of 50 months. To m
statuscvo [17]

Answer:

There is an 38.21% probability that we find this lifespan for our sample average, or something even shorter.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A manufacturing firm claims that the batteries used in laptop computers will last an average of 50 months. This means that \mu = 50.

We found that the sample had a average lifespan of 47.3 months, and a standard deviation of s = 9 months. What is the probability that we find this lifespan for our sample average, or something even shorter?

We have to find the pvalue of Z when X = 47.3.

We are working with a sample mean, so we use the standard deviation of the sample in the place of \sigma. That is s = 9

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{47.3-50}{9}

Z = -0.3

Z = -0.3 has a pvalue of 0.3821.

There is an 38.21% probability that we find this lifespan for our sample average, or something even shorter.

7 0
3 years ago
But I’m trying to write a equation out of the problem
melamori03 [73]

Step-by-step explanation:

Just use a calculator it helps, when I use the calculator it helps me alot

5 0
3 years ago
What is the answer to 56 is 28% of
Alecsey [184]
To find this answer divide by the % and times by 100 
so 56/28 x 100 =200
so the answer is 200
3 0
3 years ago
Read 2 more answers
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