It is 25.6802490 tell me if you got it right and pls give me a brainialist
Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet
Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat
By Pythagoras theorem
AC^2 = AB^2 + BC^2
(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)
AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)
Therefore they have cover a distance of 25 * (under root 11)
Answer:
Graph 'B' represents the correct graph.
The correct graph is attached below.
Step-by-step explanation:
Let 'A' be the point:
Let 'B' be the point:
As point A(-1 1/2, 1/2) can be written as:
![A=\left(-\frac{3}{2},\:\frac{1}{2}\right)=\left(-1.5,\:0.5\right)](https://tex.z-dn.net/?f=A%3D%5Cleft%28-%5Cfrac%7B3%7D%7B2%7D%2C%5C%3A%5Cfrac%7B1%7D%7B2%7D%5Cright%29%3D%5Cleft%28-1.5%2C%5C%3A0.5%5Cright%29)
so plotting the point
and
on a
.
- As we know that the 2nd quadrant, in the upper left-hand corner, consists of negative values of x and positive values of y.
Thus, the point A(-1.5, 0.5) will be plotted in the 2nd quadrant at x = -1.5 and y=0.5
i.e. at x= -1.5, y = 0.5
- As we know that the 4th quadrant, the lower left-hand corner, consists of positive values of x and negative values of y.
Point B(1.5, -0.5) will be plotted in the 4th quadrant at x = 1.5 and y = -0.5
i.e. at x= 1.5, y = -0.5
Thus, graph 'B' represents the correct graph.
The correct graph is attached below.
Answer:
Please post a clearer screenshot...
Step-by-step explanation: