3 years ago

The length of a rectangle is 10 meters more than the width. if the perimeter is 52 meters, find the length and width

1 answer:

4 0

P = 2(L + W)
P = 52
L = W + 10

52 = 2(W + 10 + W)
52 = 2(2W + 10)
52 = 4W + 20
52 - 20 = 4W
32 = 4W
32/4 = W
8 = W <==== the width is 8 meters

L = W + 10
L = 8 + 10
L = 18 <==== the length is 18 meters

You might be interested in

Find the value of x.

Otrada [13]

Answer:

the value of x is 29°

hope it helps

have a nice day

5 0

3 years ago

Need help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Rudiy27

I think the equation is y= 3/5x-1 1/2

3 0

3 years ago

Solve for x. 8(x + 1) - 3(x + 4) = 7(2 - x) Ox=11 Ox=-11 Ox= -1 1 / Ox=11/

inna [77]

Answer:

1.5

Step-by-step explanation:

$8(x + 1) - 3(x + 4) = 7(2 - x) \\ 8 x + 8 - 3x - 12 = 14 - 7x \\ 8x - 3x + 7x = 14 - 8 + 12 \\ 12x = 18 \\ x = \frac{18}{12} \\ x = \frac{3}{2} \\ x = 1.5$