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Evgesh-ka [11]
3 years ago
7

PEOPLE HELP ME PLEASE STOP IGNORING MY QUESTIONS I NEED THIS DONE NOWW!!! Skylar is playing a game where the number of spaces sh

e moves is determined by the spinner to the right. Each half of the spinner –left and right– is divided into equal regions. What is the probability that Skylar will land on an even number on her next spin? Write your answer as a fraction.

Mathematics
1 answer:
AURORKA [14]3 years ago
8 0

Answer:

5/8

Step-by-step explanation:

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Jake has a rectangular garden that measures 12 feet by 14 feet. He wants to increase the area by 50% and plans to increase each
emmasim [6.3K]

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

x\approx 2.9ft

<h2>Explanation:</h2><h2 />

First of all, let's calculate the area of the original rectangular garden:

A=b\times h \\ \\ b:base \\ \\ h:height \\ \\ \\ b=12ft \\ \\ h=14ft \\ \\ \\ A=12(14) \\ \\ A=168ft^2

Jake wants to increase the area by 50%, so the new area would be:

A'=168(1.5) \\ \\ A'=252ft^2

He wants to increase the area by 50% and plans to increase each dimension by equal lengths, x, so this is represented by the figure below, therefore:

(12+x)(14+x)=252 \\ \\ 168+12x+14x+x^2-252=0 \\ \\ x^2+26x-84=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ \\ b=26 \\ \\ c=-84 \\ \\ \\ x=\frac{-26 \pm \sqrt{26^2-4(1)(-84)}}{2(1)} \\ \\ x=\frac{-26 \pm \sqrt{1012}}{2} \\ \\ \\ Two \ solutions: \\ \\ x_{1}=-13+\sqrt{253} \approx 2.9\\ \\ x_{2}=-13-\sqrt{253} \approx -28.9 \\ \\ x_{2} \ is \ discarded \ because \ it \ can't \ be \ negatives

Finally:

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

x\approx 2.9ft

<h2>Learn more:</h2>

Dilation: brainly.com/question/10945890

#LearnWithBrainly

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