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3 years ago

Which of the following equation has both -6 and 6 as possible values of c.... C²=36, c³=216, or none of the above

Mathematics

1 answer:

erastova [34]3 years ago

7 0

Answer: THe equation C²=36 can have both -6 and 6 as possible values since -6 squared is 36 and so is 6 squared

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(25 points & Brainliest, please explain)

My name is Ann [436]

Answer:

Quadratic expression

Step-by-step explanation:

5x + 3x^2 − 7

Degree of expression = 2

So it is Quadratic expression

6 0

3 years ago

Read 2 more answers

In the diagram below of triangle PQR, S is the midpoint of PR and T is the

Nina [5.8K]

Answer:

ST = 4

Step-by-step explanation:

A segment joining the midpoints of 2 sides of a triangle is half the length of the third side.

ST = $\frac{1}{2}$ PQ substitute values

- 32 + 9x = $\frac{1}{2}$ (- 5x + 28) ← multiply both sides by 2 to clear the fraction

- 64 + 18x = - 5x + 28 (add 5x to both sides )

- 64 + 23x = 28 ( add 64 to both sides )

23x = 92 ( divide both sides by 23 )

x = 4

Then

ST = - 32 + 9x = - 32 + 9(4) = - 32 + 36 = 4

5 0

3 years ago

The equation of the function is Y=4x+5.Find the value of y when<br> x=3<br> x=-2

natita [175]

The equation of the function is y = 4x + 5. Find the value of y when

x = 3

x = -2

<h3>Given:-</h3>

y = 4x + 5 [Equation]

The value of y when x = 3 , x = -2

<h2>Solution:-</h2>

y = 4x + 5 [Given equation]

$\therefore$ When x = 3 ,

y = 4 × 3 + 5 [Value of x is 3]

y = 12 + 5

<h3>y = 17 [Answer]</h3>

Again, when x = -2 ,

y = 4 × (-2) + 5 [Value of x is -2]

y = -8 + 5

<h3>y = -3 [Answer]</h3>

8 0

3 years ago

Which of the given shapes has a larger area?

Simora [160]

Answer:

Rectangle

Step-by-step explanation:

Count the units. For the triangle, A=0.5bh. 0.5(4)(6)=A. A=12

Now, for the rectangle, A=bh. A=(3)(5). A=15. The rectangle is larger

5 0

3 years ago

An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that

qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

4 0

3 years ago