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DedPeter [7]
3 years ago
7

Just answer these 4questions! (: 13 points!

Mathematics
1 answer:
Lelechka [254]3 years ago
3 0

Answer:

Step-by-step explanation:

1) GCF = Greatest common factor which would be 6x so lets get started.

6x^3+36x+48=0\\6x(x^2+6x+8)=0\\x^2+6x+8=0\\

now we solve this with by quadratic formula.

x= -\frac{b+-\sqrt{b^2-4ac} }{2a}

so a=1 , b=6, c =8

and we get two values of x which is

x=-2 \\and \\x=-4

but in the question it says we will end up with 3 solutions. Our third solution is actually x=0

because we took 6x common as the greatest common factor so

6x=0\\x=0

so now we have 3 solutions

x=-4\\x=-2\\x=0

2) (x-9)(4x+1)=0

since this equation is already in root form we equate each root to 0

(x-9)(4x+1)=0\\x-9=0\\x=9 \\4x+1=0\\4x=-1\\x=-1/4

so our solutions are x=9 and x=-1/4

3)

(x+5)^2-12=132\\(x+5)^2=132+12\\(x+5)^2=144\\

now since we need to solve using square roots we apply square roots on both sides

\sqrt{(x+5)^2}=\sqrt{144}\\x+5=+12 \\x+5=-12

since when we take the square root of a number we get positive and negative of that number example here

x+5=±12

so

x+5=12 and x+5=-12

x=7 and x=-17

4) Difference of two squares means we just need to factorize it in root form so lets begin,

4x^2-49

now if we see this expression can be written like this as well

(2x)^2-(7)^2

and if we expand this into the difference formula which is

(a-b)(a+b)\\

we get

4x^2-49=(2x-7)(2x+7)\\

where a is 2x and b is 7

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