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4 years ago

7

HELP ASAP PLEASE WILL GIVE BRAINLIEST EASY QUESTION!!!

1 answer:

musickatia [10]4 years ago

7 0

C is the answer ! Hope I’m correct

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College alcohol and drug use: In a Washington Post/Kaiser Family Foundation poll conducted from January through March 2015, 56%

natima [27]

Answer:

D)We are 95% confident that the proportion of adults (ages 17‐26) who attended college during the past 4 years and say that alcohol and drug use at their school is a big problem is between 53% and 59%.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

In this question:

95% confidence interval is (0.53, 0.59).

This means that we are 95% sure that the true proportion for the population of adults who attended college who say that alcohol is a big problem is between 0.53 and 0.59. This means that the answer is given by option D.

8 0

3 years ago

When mr.crain was driving to work in the morning, there was heavy traffic, so he was travelling at a speed of 25 mph. when he wa

katen-ka-za [31]

Answer: ur mom gay

Step-by-step explanation:

5 0

4 years ago

Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

Determine the value of x

weeeeeb [17]

I think it's 4x. I'm sorry if this is wrong at least I tried.

8 0

4 years ago

1. Assuming that the company sells all that it produces, what is the profit function?

nalin [4]

The profit function is R(x) = -0.5 (x - 50²) + 1150

The domain of P(x) is: 0 ≤ x ≤ 150
Profit when producing 50 items = 1150
Profit when producing 60 items = 1100

<h3> What is the profit function about?</h3>

Note that:

1. Profit = Revenue - cost

P (x) = 0.5 ( x - 90²) + 4050 - 40x - 100

= 0.5 ( x² - 180 + 8100 + 4050 - 40x - 100

=0.5 x² - 50x - 100

=0.5( x² - 100x) - 100

= -0.5 (x - 50²) + 1150

2. Since the minimum unit is 50.

Then x ≤ 150

X = describe the item so it need to be a negative number

x ≥ 0

Hence the domain of P(x) is: 0 ≤ x ≤ 150

3. Assume x = 50 , 60

R(50) = 1150 , R (60 ) = -0.5 (60-50)² + 1150 = 1100

4. R (x) = -0.5 (x-50)² + 1150 then 50 more unit is removed hence, Profit when producing 60 items = 1100

Therefore, The profit function is R(x) = -0.5 (x - 50²) + 1150

The domain of P(x) is: 0 ≤ x ≤ 150
Profit when producing 50 items = 1150
Profit when producing 60 items = 1100

Learn more about profit function from

brainly.com/question/16866047

#SPJ1

5 0

2 years ago