Question

Plz help with exponents questions

Answer 1

1)
$5^{-8}\times 5^{-4} = 5^{-8 +(-4)} = 5^{-8-4} = 5^{-12}$

The answer is D

2)
$3^{-6-x} = 3^{4}\\-6-x=4\\x = -10$

The answer is A

3)
$(10^6) ^x = 10^{-18}\\6x = -18\\x=-3$

The answer is -3

4)
$\frac{5^{-6}\times 5^2 }{5^{-8}} = \frac{5^8 \times 5^2}{5^6} = \frac{5^{8+2}}{5^6} = \frac{5^{10}}{5^6} = 5^{10-6} = 5^4$

The answer is C

5)
$\frac{5^8}{(5^{-4})^{-3}} = \frac{5^8}{5^{-4\times -3}}=\frac{5^8}{5^{12}}= 5^{8-12} = 5^{-4}$

Your answer is -4

Answer 2

1.  5^-12 because a^m * a^n = a^m+n
2.  10 because a^m / a^n = a^m-n
3. -3 because ( a^n)^m = a^n*m
4. (5^-6 * 5^2) / 5^-4 = 5^-4 / 5^-8 = 5^-4+8 = 5^4 
5. 5^8 / ( 5^-4)^-3 = 5^8 / 5^12 = 5^8-12 = 5^-4