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Svet_ta [14]
4 years ago
13

If m/n=5/9, then m+n/n=?/?

Mathematics
1 answer:
Dafna1 [17]4 years ago
5 0
M+n= 14, and 14/9 equals 1 and 5/9. 
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Find the area pls- i need help
Tresset [83]

Answer:

1. 36 sq un

2. 40 sq un

3. 20 sq un

Step-by-step explanation:

The answer for number one is 36 square units because the rectangular area is 24 sq un and the triangular area is 12 sq un so I added them to get 36 sq un. The second answer is 40 sq un because if you cut the shape into 2 shapes you get 2 equal trapezoids. Each trapezoid is 20 sq un so I multiplied it by two to get 40 sq un. The third answer is 20 because the side triangles are 2 sq un each and the square on the bottom is 16 sq un. By the way, sq un means square units lol.

3 0
3 years ago
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The perimeter of this rectangle is 24cm. If the length is 8 cm, what is the height?
Gemiola [76]

Answer:

4

Step-by-step explanation:

P = s+s+s+s

length = 8

8x2=16

24-16=8

8 / 2 = 4

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3 years ago
A realtor listed a house that was 45 yards by 10 yards..What is the total square footage of the house
Alex17521 [72]
4050 ft is the total square footage of the house.
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A survey conducted by a leading HMO found that of 2000 women, 340 were heavy smokers and 25 had emphysema. Of those who had emph
belka [17]

Answer:

The events being a heavy smoker and having emphysema are not independent.

Step-by-step explanation:

We are given the following in the question:

Number of women = 2000

Number of heavy smoker = 340

Number of women who has emphysema = 25

Number of women who has emphysema and are heavy smoker = 21

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

P(Smoker) =

P(S) = \dfrac{340}{2000}=0.17

P(emphysema) =

P(E) = \dfrac{25}{2000}= 0.0125

P(Smoker and emphysema) =

P(S\cap E) = \dfrac{21}{2000} = 0.0105

Two events A and B are said to be independent if

P(A\cap B)=P(A)\times P(B)

Checking conditions for independence:

P(S)\times P(E) = 0.17\times 0.0125=0.002125\\P(S)\times P(E) \neq 0.0105\\P(S)\times P(E)\neq P(S\cap E)

Thus, the events being a heavy smoker and having emphysema are not independent.

3 0
3 years ago
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