Answer:
y - value of the vertex is 49.
Step-by-step explanation:
Given function is f(x) = -(x - 3)(x + 11)
f(x) = -(x² - 3x + 11x - 33)
= -(x² + 8x - 33)
= -(x² + 8x + 16 - 49)
= -[(x + 4)² - 49]
= -(x + 4)² + 49
Comparing this equation with the vertex form of a quadratic function,
f(x) = -(x - h)² + k
Where (h, k) is the vertex of the function.
Vertex of the parabola is (-4, 49)
Therefore, y-value of the vertex is 49.
Answer:
(4t − 3) (t − 6)
Step-by-step explanation:
Using AC method:
Given a quadratic ax² + bx + c, find factors of ac that add up to b. Divide those factors by a and reduce. The denominators become the coefficients and the numerators become the constants.
Here, a = 4, b = -27, and c = 18.
ac = 4 × 18 = 72
Factors of 72 that add up to -27: -3 and -24
Divide factors by a: -3/4 and -24/4
Reduce: -3/4 and -6/1
So the factored expression is:
(4t − 3) (t − 6)
Answer:
B—283 cm^2
Step-by-step explanation:
SA=πr^2 + πrl
r=5
l=13
SA=π5^2 + π5*13
SA=π25 + π65
SA=78.5398 + 204.2035
SA=282.7433
SA=283=B
9514 1404 393
Answer:
1 < 15 -2a < 7
Step-by-step explanation:
There are a couple of ways you can do this.
1) Put the minimum and maximum values of a into the expression to see what its corresponding values are:
15-2a for a=4:
15-2(4) = 7
15-2a for a=7:
15-2(7) = 1
Then ...
1 < 15-2a < 7
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2) Solve for a in terms of the value of 15-2a, then impose the limits on a.
x = 15 -2a
2a = 15 -x
a = (15 -x)/2
Now, impose the given limits:
4 < (15 -x)/2 < 7
8 < 15 -x < 14 . . . multiply by 2
-7 < -x < -1 . . . . . . subtract 15
7 > x > 1 . . . . . . . . multiply by -1
1 < 15-2a < 7 . . . . . use x=15-2a
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The vertical extent of the attached graph is the range of possible values of 15-2a. It goes from 1 to 7.
