Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
1.0% exactly 0.9743. I hope I helped!
Think of two ropes next to each other. Draw a picture if it helps. To find how much longer, start with the longer one and subtract the shorter length to get the difference, or “how much longer.”
To subtract fractions they have to be changed to the same denominator. First change 3 2/3 to a complex fraction; multiply the coefficient 3 times the denominator 3, then add the numerator. 3X3=9. 9+2=11 . 11 is now numerator, use same denominator. So you get 11/3. Then change denominator to 9. To do this you have to multiply by what? You would multiply by 3. Do the same to the numerator: 11 X 3=33. The fraction becomes 33/9. Now you can subtract. Now that both have the same denominator, you just subtract the numerators. 33-8=25. So, 33/9-8/9= 25/9
Answer:
B) 6(x+2y) + 4 = 6x + 12 y + 4
I think it's 10^-7 hope that helps
