Here, trapezoid is composed of two triangles, and one rectangle.
So, Area of rectangle = 4 * 7 = 28 cm²
Area of a triangle = 1/2 * 3 * 7 = 21/2 = 10.5 cm²
Area of Trapezoid = area of rectangle + 2(area of triangle)
= 28 + 2(10.5)
= 28 + 21 = 49
In short, Your Answer would be 49 cm²
Hope this helps!
Answer:
The answer is -19
Step-by-step explanation:
Given information -19y^2 , y=-1
-19 * y^2
-19 * (-1)^2
-19 * 1 = -19
Answer:
The coordinates of point Q' would be (5, -6) after being translated 1 unit to the right.
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
First thing you gotta do is find the common denominator.
Do this by listing factors of the denominators:
5- 5, 10, 15, 20, 25, 30
6- 6, 12, 18, 24, 30, 36
5 and 6 both have 30 in common so that's the new denominator for all 3 of the terms.
What you do to the bottom you must do to the top.
Since you multiply 5 by 6 to get 30, you must multiply 2 and 4 by 6 as well.
Since you multiply 6 by 5 to get 30, then multiply 5 by 5 as well.
The new equation is:
+
+
=
Now add the numerators together
The solution is
. Now simplify. 61 is prime, so you cannot change the fraction How many times does 30 go into 61? Two times. This gives us 2
.
Answer:
The original height of the tree is 18 m.
Step-by-step explanation:
Please see attached photo for explanation.
From the diagram, we shall determine the value of 'x'. This can be obtained by using the pythagoras theory as follow:
x² = 5² + 12²
x² = 25 + 144
x² = 169
Take the square root of both side
x = √169
x = 13 m
Finally, we shall determine the original height of the tree. This can be obtained as follow.
From the question given above, the tree was broken from a height of 5 m from the ground which form a right angle triangle with x being the Hypothenus as illustrated in the diagram.
Thus, the original height of the will be the sum of 5 and x i.e
Height = 5 + x
x = 13 m
Height = 5 + 13
Height = 18 m
Therefore, the original height of the tree is 18 m.