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3 years ago

Can someone help me, I have no clue

Mathematics

1 answer:

enyata [817]3 years ago

6 0

yes. which questions do you need me to answer?

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At the sixth grade school dance there are are 132 boys 89 girls and 14 adults

yuradex [85]

Um what is the question???

4 0

3 years ago

Read 2 more answers

Is the square root of eight a rational or irrational number

shutvik [7]

$\bf \sqrt{8}\implies \sqrt{2\cdot 2\cdot 2}\implies \sqrt{2^2\cdot 2}\implies 2\sqrt{2}$

it just so happen that √2 is an irrational number, so any product with it as a factor, will yield an irrational number as well.

factoid: Ancient Greeks were scared of irrational numbers, and they steered clear from √2.

8 0

3 years ago

X+8=-15 help again sorryyy

suter [353]

X by its self is always 1x

1x+8=-15 you have to get rid of 8 by subtracting on both sides

1x=-23 now get rid of 1 by dividing on both sides

x=-23

8 0

2 years ago

A driving exam consists of 30 multiple-choice questions. Each of the 30 answers is either right or wrong. Suppose the probabili

Butoxors [25]

Answer:

a. P(x>20)=0.19

b. P(x≥6)=0.72

c. P(x≤20)=0.81

d. A and C

Step-by-step explanation:

We know that:

1) the probability that a student makes fewer than 6 mistakes is 0.28

$P(x$

2) The probaiblity that a student makes between 6 to 20 mistakes is 0.53.

$P(6\leq x\leq20)=0.53$

We will express the proabilibities in function of the information we have.

a. Probability that a student makes more than 20 mistakes.

$P(x>20)=1-P(x\leq20)=1-(P(x20)=1-(0.28+0.53)=1-0.81=0.19$

b. Probability that the student make 6 or more mistakes

$P(x\geq6)=1-P(Px$

c. Probability that a student makes 20 mistakes at most

$P(x\leq20)=P(x$

d. A and C, because A takes a event of more than 20 mistakes and C takes the event of 20 or less mistakes. Both events cover a probability of 1.

7 0

2 years ago

HELP ASAP!!! PLEASE CHECK ALL OF THEM!

pochemuha

Answer:

A. (P+h)(x)

2x/x+4 (x-1) + x/x-1 (x+4)

2x^2-1/x^2-4

X^2+4/x^2-4

= 3x^2+3/x^2-4

B. (F-g)(x)

X^2-7x+6-x - 6

= x^2 -8x

C. (Fg)(x)

(X^2-7x+6)(x-6)

= x^3-13x^2+48x-36

D. (H/p)(x)

X/x-1 / 2x/x+4

X/x-1 / x+4/2x

= X^2+4x/2x^2-2x

A. (F+g)(3)

X^2+1 + x-4

3^2+1 + 3-4

10 -1

= 9

B. (f-g)(0)

X^2+1 - x-4

0+1 -0-4

1-4

= -3

C. (Fg)(-k)

(X^2+1) (x-4)

(-k^2+1) (-k-4)

K^3+4k^2-k-4

D. (F/g)(k-2)

X^2+1 /x-4

K-2^2+1 / k-2 -2

= K^2-4k+5 / k-4

Step-by-step explanation:

8 0

3 years ago