3 to the 1st is 3
3 to the 2nd is 9
3 to the 3rd is 27
3 to the 4th is 81
3 to the 5th is 243
3 to the 6th is 729
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer: what ever is -10 1/2
Step-by-step explanation:
Because its the lowest negative there and yea!
Answer:
f=
1
/4
y+
−1
/2
Step-by-step explanation:
Let's solve for f.
y=5x^0+4x−3
Step 1: Flip the equation.
4x+2=y
Step 2: Add -2 to both sides.
4x+2+−2=y+−2
4x=y−2
Step 3: Divide both sides by 4.
4x
/4
=
y−2
/4
x=
1
/4
y+
−1
/2
=f=
1
/4
y+
−1
/2
<h3><em><u>brainliest please?</u></em></h3>
