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Julli [10]
4 years ago
6

What’s the square root of 6

Mathematics
1 answer:
schepotkina [342]4 years ago
7 0

Answer:

2.44948974

Hope I could help.

Brainliest plz ;)

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if R and S are two points in a plane, the perpendicular bisector of line RS is the set of all points equidistant from R and S. T
vfiekz [6]
The answer to this question should be True. The perpendicular bisector, by definition, is the midpoint between two points that forms a right angle with them. It must be equidistant from R and S in order to be a perpendicular bisector. 
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I don't understand this question I am in need of help
Sati [7]
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3 years ago
Let r3 have the euclidean inner product. let u = (-1, 1, 1) and v = (-7, 6, 15). if ||ku + v||= 7, what is k? give the exact ans
amm1812
Mak\mathbf u+\mathbf v=k(-1,1,1)+(-7,6,15)=(-k-7,k+6,k+15)

Recall that for a vector \mathbf x\in\mathbb R^n, we have \|\mathbf x\|=\sqrt{\mathbf x\cdot\mathbf x}. So we have

\|k\mathbf u+\mathbf v\|=\sqrt{(k\mathbf u+\mathbf v)(k\mathbf u+\mathbf v)}=7
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3 0
3 years ago
the 43rd term of an arithmetic sequence is -671 and the 52nd term is -806. find the first term and the common difference.
Bond [772]

Answer:

First term = -41.

Common difference = -15.

Step-by-step explanation:

nth term: an = a1 + (n - 1)d  where a = first term and d = the common difference.

-671 = a1 + (43 - 1)d

-806 = a1 +(52 - 1)d

-671  = a1 + 42d

-806 = a1 + 51d

Subtracting ( to eliminate a1):

-671 - (-806) = 42d - 51d

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d = -15

Substitute for d in the first equation:

-671 = a1 + 42*-15

-671 = a1 - 630

a1 = -671 + 630 = -41.

3 0
3 years ago
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