The relationship between the elapsed time, t, in years, since Takumi started studying his tree, and the total number of its branches, N(t), is modeled by the function:

$N(t) = 63. 2^t$

For illustration, let us take the growth for the first three years after he started studying the number of branches.

$When \:t=1, N(1) = 63. 2^1=126\\When \:t=2, N(2) = 63. 2^2=252\\When \:t=3, N(3) = 63. 2^3=504\\504\div 252=252\div 126=2$

We notice that for each subsequent year, the number of branches doubles.

Therefore:

Every year, the number of branches grows by a factor of 2.

8 0

4 years ago

In ΔVWX, w = 780 cm, ∠V=21° and ∠W=146°. Find the length of x, to the nearest 10th of a centimeter.

wariber [46]

Complete Question

In ΔVWX, w = 780 cm, ∠X =21° and ∠W=146°. Find the length of x, to the nearest 10th of a centimeter.

Answer:

499.9cm

Step-by-step explanation:

We solve for length x using the Sine rule

w/ sin W = x /sin X

Cross Multiply

x × sin W = w × sin X

x = w × sin X/ sin W

x = 780 × sin 21°/ sin 146°

x = 499.88 cm

Approximately to nearest tenth = 499.9cm

8 0

3 years ago

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