Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

so.. that'd be the V(x) for such box, now, where is the maximum point at?

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.
so, the volume will then be at
Answer:
14). 2nd quadrant
15). 1st quadrant
Step-by-step explanation:
14).Coordinates of a point → J(-8, -12)
Coordinates of the new point J' after reflection of x-axis will follow the rule,
(x, y) → (x, -y)
Coordinates of J' → (-8, 12)
Therefore, point J' will lie in 2nd quadrant.
15). Coordinates of a point → W(-6, 7)
Rule for the rotation by 90°clockwise about the origin,
(x, y) → (y, -x)
Coordinates of point W → (-6, 7)
Following this rule,
W(-6, 7) → W'(7, 6)
Therefore, point W' will lie in the first quadrant.
Answer:
so im guessing the remainder of hw problems->
Step-by-step explanation:
24-7 =17 math problems left from doing some lunch
17-7= 10 math so its 10 math problems left