Question

Find the missing part. L=8, w=4, h=2. Find the diagonal of (d) of the retangular solid

Answer 1

The diagonal of the rectangular solid is $d=2 \sqrt{21}$

Explanation:

The length of the rectangular solid is $l=8$

The width of the rectangular solid is $w=4$

The height of the rectangular solid is $h=2$

We need to determine the diagonal of the rectangular solid.

The diagonal of the rectangular solid can be determined using the formula,

$d=\sqrt{l^{2}+w^{2}+h^{2}}$

Substituting the values $l=8$, $w=4$ and $h=2$ , we get,

$d=\sqrt{8^{2}+4^{2}+2^{2}}$

Squaring the terms, we get,

$d=\sqrt{64+16+4}$

Adding the terms, we have,

$d=\sqrt{84}$

Simplifying, we have,

$d=2 \sqrt{21}$

Thus, the diagonal of the rectangular solid is $d=2 \sqrt{21}$