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3 years ago

3. What is the solution to the equation 5x + 7 + 2 x = 7(2x + 3) - 63?

Mathematics

2 answers:

Scrat [10]3 years ago

6 0

Step-by-step explanation:

5x+7+2x=7(2x+3)-63

We move all terms to the left:

5x+7+2x-(7(2x+3)-63)=0

We add all the numbers together, and all the variables

7x-(7(2x+3)-63)+7=0

We calculate terms in parentheses: -(7(2x+3)-63), so:

7(2x+3)-63

We multiply parentheses

14x+21-63

We add all the numbers together, and all the variables

14x-42

Back to the equation:

-(14x-42)

We get rid of parentheses

7x-14x+42+7=0

We add all the numbers together, and all the variables

-7x+49=0

We move all terms containing x to the left, all other terms to the right

-7x=-49

x=-49/-7

x=+7 - Answer

icang [17]3 years ago

3 0

Answer:

x= 7

Step-by-step explanation:

5x+7+2x= 7(2x+3)-63

Distribute into the parenthesis.

5x+7+2x= 14x+21-63

Add common multiples and constants.

(5x+2x)+7= 14x+ (21-63)

7x+7= 14x-42

Move the variable to one side, to do that, subtract 7x to both sides.

7x+7= 14x-42

-7x -7x

7= 7x-42

Add 42 to both sides.

7= 7x-42

+42 +42

49= 7x

Now, divide both sides by 7 to isolate the variable.

49= 7x

7 7

x= 7

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HELP! PLEASE! Jackson is building a small rectangular basketball section in his backyard. The length of the section will be 1.25

Misha Larkins [42]

Answer:

Part A) $A=1.25W^2$

Part B) Length: 17.5 feet and Width: 14 feet

Step-by-step explanation:

Part A) Create an equation to represent the area of the basketball section A, in terms of the width W.

Let

L ----> the length of the rectangular basketball section

W ---> the width of the rectangular basketball section

we know that

The area of the rectangular basketball section is equal to

$A=LW$ ----> equation A

The length of the section will be 1.25 times the width of the section

$L=1.25W$ ----> equation B

substitute equation B in equation A

$A=(1.25W)W\\A=1.25W^2$

Part B) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?

we have

$A=1.25W^2\\A=245\ ft^2$

$245=1.25W^2$

solve for W

$W^2=245/1.25\\W^2=196\\W=14\ ft$

Find the value of L

substitute the value of W in the equation B

$L=1.25(14)=17.5\ ft$

therefore

The dimensions are :

Length: 17.5 feet

Width: 14 feet

8 0

3 years ago

Which relationship is a direct variation?

Setler79 [48]

Option A is the relationship which shows a direct variation.

Step-by-step explanation:

The direct variation is a relationship between two variables in which one is the multiple of the other. It is given by the relation

$\frac{y}{x}=k$

Option A:

For $x=2$ and $y=1$ ,

$\frac{y}{x}=\frac{1}{2}$

For $x=4$ and $y=2$ ,

$\frac{y}{x}=\frac{2}{4}= \frac{1}{2}$

Since, the constant k is equal for all the values of x and y in the table, this relationship is a direct variation.

Option B:

For $x=2$ and $y=4$ ,

$\frac{y}{x}=\frac{4}{2}= 2$

For $x=4$ and $y=16$ ,

$\frac{y}{x}=\frac{16}{4} =4$

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Option C:

For $x=1$ and $y=3$

$\frac{y}{x} =\frac{3}{1} =3$

For $x=2$ and $y=5$

$\frac{y}{x} =\frac{5}{2}$

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Option D:

For $x=1$ and $y=-1$

$\frac{y}{x} =\frac{-1}{1} =-1$

For $x=2$ and $y=2$

$\frac{y}{x} =\frac{2}{2} =1$

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Thus, Option A is the relationship which shows direct variation.

7 0

3 years ago

Explain which number is the "odd ball out" below 42, 9, 60, 8, 12

stiv31 [10]

Answer:

Step-by-step explanation:

because its odd

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3 years ago

602 < 620 correct? Which way is greater than < or >?

vichka [17]

Yes you are correct. 602<620. The greater sign goes this way ">". Just think of it as this, the less "<" sign looks like an L. Which stands for less. That's how I think of it.

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4 years ago

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Find the midpoint of the line segment joining the points P1 and P2 P1=(3,-4); P2=(5,4)

Mrac [35]

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4 years ago