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3 years ago

What is 9.42 as a mixed number?

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

8 0

Answer:

$9\frac{21}{50}$

Step-by-step explanation:

There are 9 wholes and 42 hundredths.

$9 \frac{42}{100}$

$\frac{42}{100}$ can be simplified to 21/50.

$9\frac{21}{50}$

lord [1]3 years ago

5 0

Answer:

9 $\frac{21}{50}$

That is the answer to the question

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Suppose that a company prints baseball cards. They claim that 30% of the cards feature rookies, 60% feature veterans, and 10% fe

liraira [26]

Answer:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

Step-by-step explanation:

On this case we need to apply a Chi squared goodness of fit test, and the correct system of hypothesis would be:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

And in order to test it we need to have observed and expected values. On this case we can calculate the Expected values like this

$E_{rookies}=50*0.3=15$

$E_{veterans}=50*0.6=30$

$E_{All stars}=50*0.1=5$

The observed values are not provided. The statistic on this case is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i) -E_i}{E_i}$

And this statistic follows a chi square distribution with k-1 degrees of freedom on this case k=3, since we have 3 groups.

We can calculate the p valu like this:

$P(\chi^2 > \chi^2_{calculated})=p_v$

And if the p value it's higher than the significance level we FAIL to reject the null hypothesis. In other case we reject the null hypothesis.

5 0

3 years ago

I think #1 is wrong but i can't figure it out

goldenfox [79]

Answer:

the mistake is x and y x is 6 and y is 4 so it would be 5x6 and 4^2 divide by 2

Step-by-step explanation:

the right one is 5x-y^2 divide 2

5x6-4^2 divide 2

5x6-16 divide 2

30-8

5 0

4 years ago

In recent year, the total receipts for the US federal government were $2154 billion. The total outlays were $2472 billion. The d

valentina_108 [34]

Answer:

4.84512 trillion US$

PLEASE GIVE ME BRAINLIEST

8 0

3 years ago

an old treasure map has the following instructions stand next to the black rock and face west. Walk 20 yards and then turn 90 de

Elza [17]

Answer:

West.

Step-by-step explanation:

An old treasure map has the following instructions: stand next to the black rock and face west. Walk 20 yards and then turn 90 degrees clockwise. Walk another 10 yards and then turn 45 degrees anticlockwise. Walk another 15 yards, reverse your directions and walk 5 yards back. Turn 135 degrees clockwise and walk another 10 yards. To determine in which direction you are now facing, the following logical reasoning must be carried out:

You start by walking 20 yards west, then turning 90 degrees clockwise, turning south. Then you walk 10 yards and turn counterclockwise 45 degrees, to the southwest. Later, you walk another 15 yards, turn the direction to the northeast, and walk 5 more yards. From the northeast turn 135 degrees clockwise to the west and walk 10 yards. Thus, the final sense in which the person is walking is to the West.

6 0

3 years ago

Use variation of parameters to find a general solution to the differential equation given that the functions y1 and y2 are linea

Gennadij [26K]

Answer:

$y_g(t) = c_1*( 2t - 1 ) + c_2*e^(^-^2^t^) - e^(^-^2^t^)* [ t^3 + \frac{3}{4}t^2 + \frac{3}{4}t ]$

Step-by-step explanation:

Solution:-

- Given is the 2nd order linear ODE as follows:

$ty'' + ( 2t - 1 )*y' - 2y = 6t^2 . e^(^-^2^t^)$

- The complementary two independent solution to the homogeneous 2nd order linear ODE are given as follows:

$y_1(t) = 2t - 1\\\\y_2 (t ) = e^-^2^t$

- The particular solution ( yp ) to the non-homogeneous 2nd order linear ODE is expressed as:

$y_p(t) = u_1(t)*y_1(t) + u_2(t)*y_2(t)$

Where,

$u_1(t) , u_2(t)$ are linearly independent functions of parameter ( t )

- To determine [ $u_1(t) , u_2(t)$ ], we will employ the use of wronskian ( W ).

- The functions [ $u_1(t) , u_2(t)$ ] are defined as:

$u_1(t) = - \int {\frac{F(t). y_2(t)}{W [ y_1(t) , y_2(t) ]} } \, dt \\\\u_2(t) = \int {\frac{F(t). y_1(t)}{W [ y_1(t) , y_2(t) ]} } \, dt \\$

Where,

F(t): Non-homogeneous part of the ODE

W [ y1(t) , y2(t) ]: the wronskian of independent complementary solutions

- To compute the wronskian W [ y1(t) , y2(t) ] we will follow the procedure to find the determinant of the matrix below:

$W [ y_1 ( t ) , y_2(t) ] = | \left[\begin{array}{cc}y_1(t)&y_2(t)\\y'_1(t)&y'_2(t)\end{array}\right] |$

$W [ (2t-1) , (e^-^2^t) ] = | \left[\begin{array}{cc}2t - 1&e^-^2^t\\2&-2e^-^2^t\end{array}\right] |\\\\W [ (2t-1) , (e^-^2^t) ]= [ (2t - 1 ) * (-2e^-^2^t) - ( e^-^2^t ) * (2 ) ]\\\\W [ (2t-1) , (e^-^2^t) ] = [ -4t*e^-^2^t ]\\$

- Now we will evaluate function. Using the relation given for u1(t) we have:

$u_1 (t ) = - \int {\frac{6t^2*e^(^-^2^t^) . ( e^-^2^t)}{-4t*e^(^-^2^t^)} } \, dt\\\\u_1 (t ) = \frac{3}{2} \int [ t*e^(^-^2^t^) ] \, dt\\\\u_1 (t ) = \frac{3}{2}* [ ( -\frac{1}{2} t*e^(^-^2^t^) - \int {( -\frac{1}{2}*e^(^-^2^t^) )} \, dt] \\\\u_1 (t ) = -e^(^-^2^t^)* [ ( \frac{3}{4} t + \frac{3}{8} )] \\\\$

- Similarly for the function u2(t):

$u_2 (t ) = \int {\frac{6t^2*e^(^-^2^t^) . ( 2t-1)}{-4t*e^(^-^2^t^)} } \, dt\\\\u_2 (t ) = -\frac{3}{2} \int [2t^2 -t ] \, dt\\\\u_2 (t ) = -\frac{3}{2}* [\frac{2}{3}t^3 - \frac{1}{2}t^2 ] \\\\u_2 (t ) = t^2 [\frac{3}{4} - t ]$

- We can now express the particular solution ( yp ) in the form expressed initially:

$y_p(t) = -e^(^-^2^t^)* [\frac{3}{2}t^2 + \frac{3}{4}t - \frac{3}{8} ] + e^(^-^2^t^)*[\frac{3}{4}t^2 - t^3 ]\\\\y_p(t) = -e^(^-^2^t^)* [t^3 + \frac{3}{4}t^2 + \frac{3}{4}t - \frac{3}{8} ] \\$

Where the term: 3/8 e^(-2t) is common to both complementary and particular solution; hence, dependent term is excluded from general solution.

- The general solution is the superposition of complementary and particular solution as follows:

$y_g(t) = y_c(t) + y_p(t)\\\\y_g(t) = c_1*( 2t - 1 ) + c_2*e^(^-^2^t^) - e^(^-^2^t^)* [ t^3 + \frac{3}{4}t^2 + \frac{3}{4}t ]$

3 0

3 years ago