I think the answer is B. Because if you multiply 6x8 it’s 48 divided by 2 equals 24
There´s PowToon, GoAnimate, ToonBoom. There are more, but these are the ones that I know about. I hope that I helped. Have a good day!
The recommended secure protocol for voice and video applications is the Secure<span> Real-time Transport </span>Protocol<span> (SRTP) protocol. SRTP is a Real-time Transport </span>Protocol (RTP) profile used to to provide encryption, message authentication and integrity.
The default cipher of SRTP is the Advanced Encryption Standard<span> (AES) .</span>
Answer:
Print.. is your answer...
Answer:
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int inputYear;
boolean isLeapYear;
isLeapYear = false;
inputYear = scnr.nextInt();
// If a year is divisible by 400, then it is a leap year
if (inputYear % 400 == 0)
isLeapYear = true;
// If a year is divisible by 100, then it is not a leap year
if (inputYear % 100 == 0)
isLeapYear = false;
// If a year is divisible by 4, then it is a leap year
if (inputYear % 4 == 0)
isLeapYear = true;
if(isLeapYear)
System.out.println(inputYear + " is a leap year.");
else
System.out.println(inputYear + " is not a leap year.");
}
}
Explanation:
- Take the year as an input from user and store it to inputYear variable.
- If the year is a century year, check if the year is divisible by 400 ( the year must be evenly divisible by 400 ), then set the boolean isLeapYear to true. If a year is divisible by 100, then set the boolean isLeapYear to false. If a year is divisible by 4, then set the boolean isLeapYear to true.
- Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.
Output:
1712
1712 is a leap year.