Help me I have so many of these
1 answer:
You might be interested in
Answer:
option C
c. least: $101
greatest: $1001
Step-by-step explanation:
A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.
Sum of 10 prizes = 5510
100 is the difference. there is a common difference d=100
So its a arithmetic sequence
the sum formula for arithmetic sequence is
Sn = 5510, n=10 n d= 100 we need to find out first term a1
5510 = 5 (2a1 + 900)
5510 = 10a1 + 4500
Subtract 4500 on both sides
1010= 10a1
divide by 10 on both sides
a1 = 101
so first term that is least term is 101
To find out greatest term we use formula
a(10) = 101 + (10-1)100
= 101 + 900= 1001
greatest is 1001
Given:
To find:
The quadrant of the terminal side of and find the value of
.
Solution:
We know that,
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II: Only sin and cosec are positive.
In Quadrant III: Only tan and cot are positive.
In Quadrant IV: Only cos and sec are positive.
It is given that,
Here cos is positive and sine is negative. So, must be lies in Quadrant IV.
We know that,
It is only negative because lies in Quadrant IV. So,
After substituting , we get
Therefore, the correct option is B.