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2 years ago

Factor completely 7x²-9x-10

Mathematics

2 answers:

prohojiy [21]2 years ago

7 0

(X - 2)(7x + 5) this should be your answer

Shtirlitz [24]2 years ago

5 0

Answer:

First, assign a value to x. x will be 2 in this case.

Next, multiply x by itself, because that is what exponent 2, or squared, means. 2 x 2 = 4

Now, multiply 4 by 7. 4 x 7 = 28

Next, find the value of 9x.

The value of 9x will be 9 times a number, x, also known as 2 in this scenario. 9 x 2 = 18

Then, subtract 28 from 18. 28 - 18 = 10

Lastly, subtract 10. 10 - 10 = 0

Therefore,

The answer is 0. Product may vary depending on value assigned to x.

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Write 169=13^2 in Logarithmic form

wariber [46]

Answer:

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Step-by-step explanation:

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An object with a starting velocity of 15 m/s accelerates at 3 m/s2. How far does the object travel within 10 seconds?

Anna007 [38]

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Step-by-step explanation:

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3 years ago

What is the distance between the points (-1,-9) and (4,-2)?

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$\sqrt{74}$ , or 8.60

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2 years ago

The mean length of 7 childrens' index finger is 9.4cm. The mean length of 5 adults' index finger is 10.2cm. What is the mean len

Deffense [45]

Answer:

9.73 cm to 2 DP

Step-by-step explanation:

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= 116.8 cm

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= 116.8/12

= 9.73 cm to 2 DP.

3 0

2 years ago

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A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

7 0

3 years ago

Factor completely 7x²-9x-10​

Factor completely 7x²-9x-10