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anygoal [31]
3 years ago
11

How do you solve this equation log(3x+1)=5

Mathematics
2 answers:
mezya [45]3 years ago
8 0

Answer:

x = 33333

Step-by-step explanation:

If you take the left and right-hand side and raise 10 to the power of it, you get:

10^{log(3x+1)} = 10^5

Which simplifies to:

3x+1 = 100000

Because 10^{log(x)} = x

Solving it gives:

3x = 100000 - 1 = 99999

x = 33333

Len [333]3 years ago
7 0

log_{10} 3x+1=5

3x+1=10^5

3x+1=100000

3x=99999

x=333333


Just remember that in the form of log_ab=x, you get a^x=b.


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1. replace f(x) with y
2. swich x and y places
3. solve for y
4. replace y with f⁻¹(x) (read 'f inverse')

so we have
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