D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Here is your answers worked out !
Answer:
X<7. Graph 7. Then put a open circle and arrow it going left! And there you go.
Step-by-step explanation:
Add 18 to both sides. Since -2x has a negative, you flip the sign to less than instead of greater than.
Answer:
49/6
Step-by-step explanation:
8×6= 48
+ the numerator
