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2 years ago

Please help with this question!

Mathematics

1 answer:

tankabanditka [31]2 years ago

8 0

Answer:

help

Step-by-step explanation:

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PLEASE HELP ME <br> *algebra 2*

Blizzard [7]

I hope this helpss.

8 0

2 years ago

Solve for X<br><br> Thank youuu

maksim [4K]

Answer:

x= -4

Step-by-step explanation:

∠LMP + ∠PMN= 180° (adj. ∠s on a str. line)

-16x +13 -20x +23= 180

bring x term to 1 side, constant to the other:

-36x= 180 -13 -23

Simplify:

-36x= 144

x= 144 ÷ (-36)

x= -4

*The sum of the angles on a straight line is 180°

6 0

2 years ago

Julia has 4 gallons 2 quarts of water. Ally needs the same amount of water but only has 12 quarts. How much more water does ally

skad [1K]

Answer: Ally would need 6 more quarts of water.
Explanation: Since 4 quarts equal 1 gallon, 4*4 = 16 + 2 = 18, Julia would have 18 quarts. Subtract 12 from 18 to get 6 quarts.

5 0

3 years ago

How do I do this?<br>*Look at the directions in the photo*

lora16 [44]

Answer:

$Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2$

Step-by-step explanation:

$We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\$

$As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2$

$For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2$

$For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2$

$Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2$

7 0

2 years ago

During a sale, cameras were discounted 30% from their original price of $295.99. To the nearest cent, how much was the camera du

Elina [12.6K]

Answer:

207.193

Step-by-step explanation:

295.99 - 30% ...........

3 0

2 years ago

Read 2 more answers

Please help with this question!​

Please help with this question!