Slope =gradient=m
Y intercept =c
Y=mx+c
Y=3x-5
Hope this helps
Answer:
(x+8, y+2) and reflect across x axis
Answer:
The taxi drivers average profit per trip is $9.50.
Step-by-step explanation:
The taxi driver provides services in Zone A and Zone B.
Let = destination is in Zone A and = destination is in Zone B.
<u>Given:</u>
The probabilities are:
The Expected profit are:
If the trip is entirely in Zone A the expected profit is, E (A - A) = $7.
If the trip is entirely in Zone B the expected profit is, E (B - B) = $8.
If the trip involves both the zones the expected profit is,
E (A - B) = E (B - A) = $12.
Determine the expected profit earned in Zone A as follows:
Determine the expected profit earned in Zone B as follows:
The total expected profit is:
Thus, the taxi drivers average profit per trip is $9.50.
Answer:
Choice A, x=1
Step-by-step explanation:
So, to start, there's two routes that you can take there. I am going to show one of these routes.
Within the image, you see two triangles, you are able to tell that these triangles share two of the same sides, because of congruency lines on each of them.
The first group of congruent sides have 1 line going through them, the second group has 2 lines going through them. Let's go with the first group.
With the first group, we are using the lines CB and FE, where the measurements on each of them are 3x+1 and x+3 respectively.
Since they are congruent, they are equal and we can just set them equal to each other.
Starting With:
3x+1 = x+3
Step 1) Cancel out the +1
3x+1 -1 = x+3 -1
3x = x+2
Step 2) Cancel out the x
3x -x = x+2 -x
2x = 2
Step 3) Divide by 2 get x by itself
2x/2 = 2/2
x=1
All done!
Answer:
a) 1316 dollars
b) 6916 dollars
Step-by-step explanation:
Last year, Goran opened an investment account with 5600. At the end of the year, the amount in the account had increased by 23.5% .
a) How much is this increase in dollars?
The increase on dollars is calculated as:
5600 × 23.5%
= 1316 dollars
b) How much money was in his account at the end of last year ?
The amount of money in his account at the end of last year is calculated as:
Increase + Initial amount invested
=( 1316 + 5600) dollars
= 6916 dollars