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3 years ago

Complete each function table. Then write the rule

1 answer:

6 0

Addition + you add the numbers together by combining them. Any odd number plus odd number is even. Any even number plus even is even and any odd plus even is odd
Subtraction - You delete numbers by numbers on top. But, when there's a smaller number minus a bigger number it doesn't work so you'd have to change it.

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9.25 or or 9 1/4

Step-by-step explanation:

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3 years ago

14 plus 5(x plus 3) minus 7

Damm [24]

14+5(x+3)-7
14+(5x+15)-7
7+5x+15
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3 years ago

HELP!!!!! ASAP PLEASE!!!!!!!!!!

Nataly_w [17]

Answer:

Tangent line states that a line in the plane of a circle that intersect the circle in exactly one point.

Common external tangent states that a common tangent that does not intersects the line segment joining the centers of circle.

Common internal tangent states that a common tangent that intersects the line segment joining the centers of circle.

Circumscribe polygon states that a polygon with all sides tangent to a circle contained within the polygon.

Therefore:

A polygon with all sides tangent to a circle contained within the polygon = Circumscribe polygon

A common tangent that intersects the line segment joining the centers of circle = Common internal tangent

A common tangent that does not intersects the line segment joining the centers of circle = Common external tangent

a line in the plane of a circle that intersect the circle in exactly one point = Tangent line

3 0

3 years ago

Write each expression in simplified radical form PLEASE HELP ITS DUE FRIDAY AND I DONT UNDERSTAND THIS AT ALL REALLY BAD TEACHER

Nonamiya [84]

Answer:

1) The simplified radical form is $\sqrt{36x^2}=6x$

2) The simplified radical form is $\sqrt{72x^3}=6x\sqrt{2x}$

3) The simplified radical form is $\sqrt{15x^8}=\sqrt{15}x^4$

4) The simplified radical form is $\sqrt{36x^7}=6x^3\sqrt{x}$

Step-by-step explanation:

1) Given expression is $\sqrt{36x^2}$

To find the simplified radical form of the given expression :

$\sqrt{36x^2}$

$=\sqrt{36\times x^2}$

$=\sqrt{36}\times \sqrt{x^2}$

$=\sqrt{6\times 6}\times \sqrt{x\times x}$

$=6\times x$

$\sqrt{36x^2}=6x$

Therefore the simplified radical form is $\sqrt{36x^2}=6x$

2)Given expression is $\sqrt{72x^3}$

To find the simplified radical form of the given expression :

$\sqrt{72x^3}$

$=\sqrt{72\times x^3}$

$=\sqrt{72}\times \sqrt{x^3}$

$=\sqrt{9\times 8}\times \sqrt{x\times x\times x}$

$=\sqrt{9}\times \sqrt{8}\times x\sqrt{x}$

$=3\times 2\sqrt{2}\times x\sqrt{x}$

$\sqrt{72x^3}=6x\sqrt{2x}$

Therefore the simplified radical form is $\sqrt{72x^3}=6x\sqrt{2x}$

3) Given expression is $\sqrt{15x^8}$

To find the simplified radical form of the given expression :

$\sqrt{15x^8}$

$=\sqrt{15\times x^8}$

$=\sqrt{15}\times \sqrt{x^8}$

$=\sqrt{5\times 3}\times \sqrt{x^4\times x^4}$

$=\sqrt{15}\times x^4$

$\sqrt{15x^8}=\sqrt{15}x^4$

Therefore the simplified radical form is $\sqrt{15x^8}=\sqrt{15}x^4$

4) Given expression is $\sqrt{36x^7}$

To find the simplified radical form of the given expression :

$\sqrt{36x^7}$

$=\sqrt{36\times x^7}$

$=\sqrt{36}\times \sqrt{x^7}$

$=\sqrt{6\times 6}\times \sqrt{x^3\times x^3\times x}$

$=6\times x^3\sqrt{x}$

$\sqrt{36x^7}=6x^3\sqrt{x}$

Therefore the simplified radical form is $\sqrt{36x^7}=6x^3\sqrt{x}$

3 0

3 years ago