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Readme [11.4K]
3 years ago
6

What is 20 percent of 3500

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0
20% = 20/100 = 1/5
1/5 of 3500
1/5 X 3500/1 = 3500/5
3500/5 = 700.
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carley beat the school record for the 400 meter run by 1.3 seconds. if she ran the race in 55.7 seconds what was the record?
Vika [28.1K]

Answer:

If Carley ran the 400 meter run in a total of 55.7 seconds and she beat the record by 1.3 seconds, you would add 55.7 and 1.3

55.7+1.3= 57 seconds

The past school record for the girls 400 meter run was 57 seconds

Hope this helps ;)

4 0
3 years ago
Geometry Special Quadrilaterals show work please
Charra [1.4K]

Answer:

a = 16

w = 125

x = 120

y = 55

Step-by-step explanation:

<u>FINDING 'a'</u>

31 = a + 46 / 2

62 = a + 46

16 = a

<u>FINDING 'w'</u>

* This section looks Non-Isosceles trapezoid so I will be following the rule according it

w + 55 = 180

w = 125

<u>FINDING 'y'</u>

y = 55

- Because of corresponding angles

<u>FINDING 'x'</u>

* In this case it looks like we are still dealing w/ an non-isosceles trapezoid.

x + 60 = 180

x = 120

Hope this helped ^^

(Please inform me of any mistakes or misunderstandings!)

6 0
3 years ago
2x=5 what do we divide by?
larisa [96]
We divide by 2 on both sides.

We get the final answer as

x = 5/2 = 2.5
8 0
3 years ago
Read 2 more answers
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
What is the quotient of 78,600 + 12?
creativ13 [48]

The quotient of 78,600 and 12 is 6,550

7 0
3 years ago
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