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ra1l [238]
3 years ago
14

What is the simplified form of the quantity 1 over b minus 1 over a all over the quantity 1 over b plus 1 over a?

Mathematics
1 answer:
jolli1 [7]3 years ago
4 0

Option B: (b-a)/(b+a) is the correct answer

Step-by-step explanation:

The given expression is;

\frac{\frac{1}{b}-\frac{1}{a}}{\frac{1}{b}+\frac{1}{a}}

First of all we have to take LCM in both numerator and denominator

So,

=\frac{\frac{b-a}{ab}}{\frac{b+a}{ab}}

The reciprocal of the denominator will be multiplied with the numerator for simplification

So,

=\frac{b-a}{ab} * \frac{ab}{b+a}\\= \frac{b-a}{b+a}

Hence,

Option B: (b-a)/(b+a) is the correct answer

Keywords: Fractions, expressions

Learn more about fractions at:

  • brainly.com/question/5424148
  • brainly.com/question/5461619

#LearnwithBrainly

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1) Inverse function: f^{-1}(x)=g(x)=\frac{x+4}{3}

2) f(1) = -1, g(-1) = 1

3) f(g(x))=g(f(x))=x

Step-by-step explanation:

1)

In this first method, we want to find the inverse function of f(x).

The original function is:

f(x) = 3x-4

We rewrite it as

y=3x-4

We swap the name of the variables:

x=3y-4

Adding +4 on both sides:

x+4=3y-4+4\\x+4=3y

And dividing by 3 on both sides:

y=\frac{x+4}{3}

which is identical to g(x):

g(x)=\frac{x+4}{3}

2)

In this second method, we want to use the output of one function as input to the other function, and show that the output value is equal to the imput value.

We start using the function

f(x)=3x-4

We choose x=1. We find:

f(1)=3(1)-4=3-4=-1

Now we use this output value as input in the function

g(x)=\frac{x+4}{3}

Substituting x=-1,

g(-1)=\frac{-1+4}{3}=\frac{3}{3}=1

So, the final output value (1) is equal to the input value (1).

3)

Here we want to verify that the two are inverse functions by showing that

f(g(x))=x

We have

f(x)=3x-4\\g(x)=\frac{x+4}{3}

Substituting g(x) into f(x),

f(g(x))=3g(x)-4 = 3(\frac{x+4}{3})-4=(x+4)-4=x

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g(f(x))=x

Substituting g(x) into f(x), we get

g(f(x))=\frac{f(x)+4}{3}=\frac{(3x-4)+4}{3}=\frac{3x-4+4}{3}=\frac{3x}{3}=x

So, the two functions are one the inverse of the other.

Learn more about inverse functions:

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