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3 years ago

It says to solve for x but I don’t know how to do it

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

0 & 3

Step-by-step explanation:

(1/7)x² - (3/7)(x) = 0

Take (1/7)x common

(x/7)(x - 3) = 0

(x/7) = 0 when x = 0

x - 3 = 0 when x = 3

dalvyx [7]3 years ago

6 0

Answer: x = {0, 3}

Step-by-step explanation:

First, clear the denominator.

Then move everything to one side so zero is on the other side (because it is a quadratic equation).

Next, factor the quadratic equation.

Finally, solve each factor.

$\dfrac{1}{7}x^2=\dfrac{3}{7}x\\\\\\7\bigg(\dfrac{1}{7}x^2\bigg)=7\bigg(\dfrac{3}{7}x\bigg)\\\\\\x^2=3x\\\\\\x^2-3x=0\\\\\\x(x-3)=0\\\\\\x=0\qquad x-3=0\\\\\\.\qquad \qquad x=3\\\\\\\large\boxed{x=\{0,3\}}\\$

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What number times itself equals 196?

leonid [27]

number times itself equals 196

$= n * n = 196$

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8 0

2 years ago

Read 2 more answers

(07.05) Graph the first six terms of a sequence where a = -10 and d = 3.

butalik [34]

Answer:

Step-by-step explanation:

Using the formular, Sn = n/2(2a + (n - 1)d)

where, n = 6: Sn = 6/2( -20 + 5(3)) = 3(15 - 20)

∴ Sn = 15

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2 years ago

Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0