All categories

3 years ago

It says to solve for x but I don’t know how to do it

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

0 & 3

Step-by-step explanation:

(1/7)x² - (3/7)(x) = 0

Take (1/7)x common

(x/7)(x - 3) = 0

(x/7) = 0 when x = 0

x - 3 = 0 when x = 3

dalvyx [7]3 years ago

6 0

Answer: x = {0, 3}

<u>Step-by-step explanation:</u>

First, clear the denominator.

Then move everything to one side so zero is on the other side (because it is a quadratic equation).

Next, factor the quadratic equation.

Finally, solve each factor.

$\dfrac{1}{7}x^2=\dfrac{3}{7}x\\\\\\7\bigg(\dfrac{1}{7}x^2\bigg)=7\bigg(\dfrac{3}{7}x\bigg)\\\\\\x^2=3x\\\\\\x^2-3x=0\\\\\\x(x-3)=0\\\\\\x=0\qquad x-3=0\\\\\\.\qquad \qquad x=3\\\\\\\large\boxed{x=\{0,3\}}\\$

You might be interested in

HELP ASAP!!

olga2289 [7]

Answer:

62.5%

Step-by-step explanation:

150/240=0.625

you do 0.625x100 to get the percent.

8 0

2 years ago

Look at the picture! Express the following set in set-builder notation ?

Alex

Answer:

A. E={ $x|x\in N$ and $x$ is a multiple of 8}

Step-by-step explanation:

Let $x$ represent the set of natural numbers. Then we can write;

$x\in N$ .

The set of all natural numbers that are multiples of 8 is then written as;

$x\in N$ and $x$ is a multiple of 8.

E is the set of natural numbers that are multiples of 8 can then be written in set builder notation as;

E={ $x|x\in N$ and $x$ is a multiple of 8}

The correct choice is A

7 0

3 years ago

I NEED HELP WITH THIS PLEASE

11Alexandr11 [23.1K]

Answer:

Perimeter = Side1 + Side2 + Side3

4x + 3y = 5x - 3y + x + 4y + Side3

4x + 3y = 6x + y + Side3

-2x + 2y = y + Side3

Step-by-step explanation:

I WISH IT COULD HELP

8 0

2 years ago

Add a sign: 2 4 9 6=992

melomori [17]

2 4 9 6=992 hfghubdfb gg by

8 0

2 years ago

What is the value of y in the solution to the system of equations? 1/3x + 1/4y = 1 2x-3y=-30

Zepler [3.9K]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}\dfrac{1}{3}x+\dfrac{1}{4}y=1&\text{multiply both sides by 12}\\2x-3y=-30\end{array}\right\\\left\{\begin{array}{ccc}12\!\!\!\!\!\diagup^4\cdot\dfrac{1}{3\!\!\!\!\diagup_1}x+12\!\!\!\!\!\diagup^3\cdot\dfrac{1}{4\!\!\!\!\diagup_1}y=12\cdot1\\2x-3y=-30\end{array}\right\\\left\{\begin{array}{ccc}4x+3y=12\\2x-3y=-30&\text{multiply both sides by (-2)}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}4x+3y=12\\-4x+6y=60\end{array}\right}\qquad\text{add both sides of the equations}$

$.\qquad9y=72\qquad\text{divide both sides by 9}\\.\qquad y=8$

6 0

3 years ago