Question

It says to solve for x but I don’t know how to do it

Answer 1

Answer:

0 & 3

Step-by-step explanation:

(1/7)x² - (3/7)(x) = 0

Take (1/7)x common

(x/7)(x - 3) = 0

(x/7) = 0 when x = 0

x - 3 = 0 when x = 3

Answer 2

Answer:  x = {0, 3}

Step-by-step explanation:

First, clear the denominator.

Then move everything to one side so zero is on the other side (because it is a quadratic equation).  

Next, factor the quadratic equation.

Finally, solve each factor.

$\dfrac{1}{7}x^2=\dfrac{3}{7}x\\\\\\7\bigg(\dfrac{1}{7}x^2\bigg)=7\bigg(\dfrac{3}{7}x\bigg)\\\\\\x^2=3x\\\\\\x^2-3x=0\\\\\\x(x-3)=0\\\\\\x=0\qquad x-3=0\\\\\\.\qquad \qquad x=3\\\\\\\large\boxed{x=\{0,3\}}$