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Vesna [10]
3 years ago
12

It says to solve for x but I don’t know how to do it

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

0 & 3

Step-by-step explanation:

(1/7)x² - (3/7)(x) = 0

Take (1/7)x common

(x/7)(x - 3) = 0

(x/7) = 0 when x = 0

x - 3 = 0 when x = 3

dalvyx [7]3 years ago
6 0

Answer:  x = {0, 3}

<u>Step-by-step explanation:</u>

First, clear the denominator.

Then move everything to one side so zero is on the other side (because it is a quadratic equation).  

Next, factor the quadratic equation.

Finally, solve each factor.

\dfrac{1}{7}x^2=\dfrac{3}{7}x\\\\\\7\bigg(\dfrac{1}{7}x^2\bigg)=7\bigg(\dfrac{3}{7}x\bigg)\\\\\\x^2=3x\\\\\\x^2-3x=0\\\\\\x(x-3)=0\\\\\\x=0\qquad x-3=0\\\\\\.\qquad \qquad x=3\\\\\\\large\boxed{x=\{0,3\}}\\

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The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.

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Dividing Row 1 by -3 gives:

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Adding Row 2 to Row 3 gives;

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Dividing Row 2 by -2, and Row 3 by 18 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& 1 &  -7\\ 0&0  &1  \\\end{bmatrix}

The above matrix is in the row echelon form

Learn more about the row echelon form here:

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