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3 years ago

12

Suppose two linear equations have the same slope. Is it true that the point (3, 4) is the only point that satisfies both equatio

ns?

1 answer:

IrinaVladis [17]3 years ago

8 0

No but it is true that the two equations are parallel.

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Match each angle below with its measurement.

brilliants [131]

A = 90 degrees
B = 50 degrees
D = 140 degrees
E = 40 degrees
HOPE THIS HELPS!

7 0

3 years ago

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2x+3=-7 what does x equal

ollegr [7]

Answer:-5

Step-by-step explanation:

2x+3=-7

2x=-7-3

x=-10/2

so,

x=-5

5 0

3 years ago

What is the area of the figure below

jek_recluse [69]

Answer:

Option A

Step-by-step explanation:

Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF

Area of ΔABH = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(6)(8-5)$

= 9 in²

Area of the trapezoid = $\frac{1}{2}(CG+BH)(\text{Distance between these lines})$

= $\frac{1}{2}(6+4)(5)$

= 25 in²

Area of ΔDEF = $\frac{1}{2}(8)(6)$

= 24 in²

Therefore, area of the given figure = 9 + 25 + 24

= 58 in²

Option A will be the correct option.

3 0

3 years ago

Which is a solution to (x – 3)(x + 9) = –27?<br><br> x = –9<br> x = –3<br> x = 0<br> x = 6

Margarita [4]

Expand
x²+6x-27=-27
add 27 both sides
x²+6x=0
factor
x(x+6)=0
set to zero

x=0

x+6=0
x=-6

x=0 or -6

answer is 0 since -6 is not listed

8 0

4 years ago

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Solve this radical equation for x. Show all steps.<br><br> x=square root 6x-9

Gre4nikov [31]

$x = \sqrt{6x - 9} \\$

Square both sides.

$x^2 = 6x - 9$

Move all terms to one side.

$x^2 - 6x + 9 = 0$

Simplify using AC method.

$x^2 - 6x + 9 = (x - 3)(x - 3)$

<h3>x = 3</h3>

6 0

3 years ago

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