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3 years ago

Given the following exponential function, identify whether the change represents

Mathematics

1 answer:

viktelen [127]3 years ago

4 0

Answer:

decay, 94%

Step-by-step explanation:

when multiplying by a decimal between 0 and 1, the base value (630 in this case) is being decayed over time, by more and more each time you multiply by that decimal (.94 in this case)

however, of yoy were to multiply by any number greater than one, you're exponentially increasing the base value each time.

the percentage of increase or decrease is the decimal value from earlier youre multiplying by, except with the decimal moved two places to the right (.94 goes to 94%)

You might be interested in

Average for 5,16,20,14

Pepsi [2]

Answer:

13.75

Step-by-step explanation:

you need to add them all

5+16+20+14

divide the sum of those by 4

55/4=13.75

4 0

3 years ago

Bradley invested an average of $550 per month since age 49 in various securities for his retirement savings. His investments ave

avanturin [10]

To estimate the amount Bradley would have at age 73 if he started investing in 40 we use the future annuity formula given by:
A=P[((1+r)^n-1)/r]
where:
P=principle
r=rate
n=time
thus plugging in the values we get:
A=12×550=$6600
n=73-40=33
r=7%
hence
A=6600[((1.07)^33-1)/0.07]
simplifying the ^ we get:
A=784,960.6054
Hence the answer is: $784, 960.6054

6 0

4 years ago

The mean weight of 10 randomly selected newborn babies at a local hospital is 7.14 lbs and the standard deviation is 0.87 lbs. A

sergejj [24]

Answer:

a) $ME= 1.83 \frac{0.87}{\sqrt{10}}=0.5035$

b) 90% of all samples of size 10 have sample means within 0.5035 of the population mean.

c) The 90% confidence interval would be given by (6.636;7.643)

d) Yes, since the lower limit for the 90% confidence interval is higher than the value of 6.5 we can conclude that the true mean is significantly higher than 6.5 at 10% of significance. (6.636>6.5)

e) If we increase the confidence level that implies increase the margin of error. Since with more confidence level the value for the critical value $t_{\alpha/2}$ increase. So then the new interval would be wider than the original.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=7.14$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=0.87 represent the sample standard deviation

n=10 represent the sample size

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And the margin of error is given by:

$ME= t_{\alpha/2}\frac{s}{\sqrt{n}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,9)".And we see that $t_{\alpha/2}=1.83$

$ME= 1.83 \frac{0.87}{\sqrt{10}}=0.5035$

Part b

90% of all samples of size 10 have sample means within 0.5035 of the population mean.

Part c

Now we have everything in order to replace into formula (1):

$7.14-1.83\frac{0.87}{\sqrt{10}}=6.637$

$7.14+1.83\frac{0.87}{\sqrt{10}}=7.643$

So on this case the 90% confidence interval would be given by (6.636;7.643)

Part d

Yes, since the lower limit for the 90% confidence interval is higher than the value of 6.5 we can conclude that the true mean is significantly higher than 6.5 at 10% of significance. (6.636>6.5)

Part e

If we increase the confidence level that implies increase the margin of error. Since with more confidence level the value for the critical value $t_{\alpha/2}$ increase. So then the new interval would be wider than the original.

7 0

4 years ago

Find the value for the side marked below.

lions [1.4K]

Answer:

y = 189.8

Step-by-step explanation:

Apply trigonometric function to find y.

Reference angle (θ) = 50°

Adjacent side = 122

Hypotenuse = y

Apply CAH, since the Hypotenuse and the Adjacent are involved.

Thus:

Cos θ = Adj/Hypo

Plug in the values

Cos 50° = 122/y

y*Cos 50° = 122

y = 122/cos 50°

y = 189.8 (beater tenth)

6 0

3 years ago

What does a vector do to a translation

Alona [7]

Answer:

A translation vector is a type of transformation that moves a figure in the coordinate plane from one location to another. In other words, a translation vector can be thought of as a slide with no rotating. The slide won’t change the shape or size of the figure, and with no rotation, the orientation won’t change either.

Step-by-step explanation:

3 0

4 years ago