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Evgesh-ka [11]
3 years ago
11

Re-arrange this polynomial so its terms

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0

Answer:

It should be 2x3 - 7x2 +5x - 15

Step-by-step explanation:

You have to look at the variable with the greatest exponential value

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A customer visiting the suit department of a certain store will purchase a suit with probability 0.22, a shirt with probability
Pachacha [2.7K]

Answer:

a. The probability that a customer purchase none of these items is 0.49

b. The probability that a customer purchase exactly 1 of these items would be of 0.28

Step-by-step explanation:

a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:

let A represents suit

B represents shirt

C represents tie

P(A) = 0.22

P(B) = 0.30

P(C) = 0.28

P(A∩B) = 0.11

P(C∩B) = 0.10

P(A∩C) = 0.14

P(A∩B∩C) = 0.06

Therefore, the probability that a customer purchase none of these items we would have to calculate the following:

1 - P(A∪B∪C)

P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)

= 0.22+0.28+0.30-0.11-0.10-0.14+0.06

= 0.51

Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49

The probability that a customer purchase none of these items is 0.49

b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:

= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2  P(A ∩ B ∩ C))

=0.51 -0.23 = 0.28

The probability that a customer purchase exactly 1 of these items would be of 0.28

6 0
3 years ago
Why are different intervals used when restricting the domains of the sine and cosine functions in the process of defining their
umka21 [38]

Answer:

See below

Step-by-step explanation:

The interval must be chosen so that the function is one-to-one, and the sine and cosine functions are not one-to-one on the same intervals.

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2 years ago
Identify the solution set of each equation or inequality using the given replacement set
-BARSIC- [3]
I believe the answer is C
8 0
3 years ago
Nitrogen and oxygen are the most abundant gases in Earth’s atmosphere. A nitrogen molecule is 0.00000000003 meters larger than a
Verdich [7]
= 3 × 10-11
(scientific notation)

= 3e-11
(scientific e notation)

= 30 × 10-^12
(engineering notation)
(trillionth; prefix pico- (p))

= 0.0000000000
<span>(real number)</span>
4 0
3 years ago
Read 2 more answers
41,000.00 minus 23,000.00
inna [77]
18,000.00.This is the answer 

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