Answer:
Step-by-step explanation:
Formula to be used is N=N0e^(kt)
N0 - amount of bacteria at time 0, which is 10g
t=2, 30g
30 = 10*e^(k*2)
3 = e^(2k)
2k = ln3
k = 0.5ln3
At t=6:
N = 10*e^(0.5ln3*6)
N = 10e^(3ln3)
N = 10e^ln27
N = 10*27 =270
So the amount of bacteria at t=6 is 270
Answer:
10
Step-by-step explanation:
1. 2(4.5)+1
2. 9+1
3. 10
Answer:
9pr = 2q^2
Step-by-step explanation:
28.
px^2 + qx + r = 0
If one root is A then the other root is 2A
We have A + 2A = -q/p and A*2A = r/p
So 3A = -q/p so A = -q/3p and A^2 = r/2p so A = √ (r / 2p)
Equating these 2 equations:-
-q/3p = √(r / 2p)
q^2 / 9p^2 = r / 2p
9p^2r = 2pq^2
9pr = 2q^2 (answer)
Answer:
i think the answer is -y^2/20 + 2y/3 - 1/4