3 years ago

Please help me with this geometry question !!

Mathematics

1 answer:

mezya [45]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

Given the rule (x, y ) → (x + 5, - y )

Add 5 to the original x- coordinate and make the y- coordinate negative.

(a)

(5, 3 ) → (5 + 5, - 3 ) → (10, - 3 )

(b)

(- 2, 7 ) → (- 2 + 5, - 7 ) → (3, - 7 )

You might be interested in

i really really really need help with this math question i’m giving away FREE points and BRAINLIEST for correct answer

Travka [436]

B is the correct answer. please mark brainliest.

8 0

3 years ago

Read 2 more answers

Last summer, an ice cream shop sold a small ice cream for $1.25 and a large ice cream for $3.75. The ice cream shop decided to r

vovangra [49]

Answer:C

Step-by-step explanation:

keeping proportional and thats the only answer where the difference is still $2.25

8 0

3 years ago

Read 2 more answers

The rabbit will never go over 75 pounds. If this rabbit is bom in July weighing 2 pounds, in which month will it weigh around 46

nexus9112 [7]

The answer is June your welcome

8 0

3 years ago

Find the circumference and area of the circle. Use 3.14 for π. Round to the nearest hundredth if necessary.

BARSIC [14]

Answer:

81.64

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A = √7 + √c and b = √63 + √d where c and d are positive integers.

mrs_skeptik [129]

Answer:

$\displaystyle a:b=\frac{1}{3}$

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

$a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]$

$b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]$

$\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]$

From [3]:

$9c=d$

Replacing into [2]:

$b=\sqrt{63}+\sqrt{9c}$

We can express 63=9*7:

$b=\sqrt{9*7}+\sqrt{9c}$

Taking the square root of 9:

$b=3\sqrt{7}+3\sqrt{c}$

Factoring:

$b=3(\sqrt{7}+\sqrt{c})$

Find the ration a:b:

$\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}$

Simplifying:

$\boxed{a:b=\frac{1}{3}}$

3 0

3 years ago