Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)
To make calculation easier, we first multiply
1.35 × 100 = 135
then we need to find how many groups of 5 are there in 135.
to do so, we simply take
135 ÷ 5 = 27
therefore, the answer is <u>27.</u>
Answer:
No solution.
Explanation:
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace f(x) with 0 and solve for x.
Answer:
The annual percentage rate of change for the population of Oregon is of 8.125%.
Step-by-step explanation:
Total percentage change:
Change multiplied by 100 and divided by the initial value.
Change: 8.7 - 4.8 = 3.9 million
Initial value: 4.8
Percentage change: 3.9*100/4.8 = 81.25%
Annual percentage rate of change
81.25% during 10 years(from 2000 to 2010).
So, per year
81.25%/10 = 8.125%
The annual percentage rate of change for the population of Oregon is of 8.125%.
Answer: x = 3/4 x = -5
Step-by-step explanation:
x+5=0
x=-5
4x-3=0
Add three to both sides
4x = 3
x=3/4
