1/10 of a pound or 1.6 ounces
The first one is 64. The second one is -64. Third is 10000
Answer:
Step-by-step explanation:
Part A
xf = xo + vo* t + 1/2 a*t^2 Subtract xo
xf - xo = 0*t + 1/2 a*t^2 multiply by 2
2(xf - xo) = at^2 divide by t^2
2(xf - xo ) / t^2 = a
Part B
Givens
xo =0
vo = 0
a = 10 m/s^2
xf = 120 m
Solution
xf = xo + vo* t + 1/2 a*t^2 Substitute the givens
120 = 0 + 0 + 1/2 * 10 * t^2 Multiply by 2
120*2 = 10* t^2
240 = 10*t^2 Divide by 10
240/10 = t^2
24 = t^2 take the square root of both sides.
√24 = √t^2
t = √24
t = √(2 * 2 * 2 * 3)
t = 2√6
Basically solve for y
minus 5x fromboth sides
-15y=-5x-60
divide both sides by -15
y=1/3x+4
Given function:
The minimum value of the function can be found by setting the first derivative of the function to zero.
Solving for x:
Substituting the value of x into the original function:
Hence, the minimum value in the given range is (-1, -0.368)
