What are the steps needed to solve the following problem: (2x - 3)(x + 4) = -5?

Mathematics

2 answers:

pashok25 [27]4 years ago

6 0

These are the steps.

1. Write out the equation.

2. FInd any whole numbers and put them together and find any variables and put them together, both in parentheses.

3. Solve both equations in parentheses.

4. Divide -5 by 3 to find x. The answer is on step 5.

$1. (2x - 3)(x + 4) = -5\\2. (-3 + 4)(2x + x) = -5\\3. (1)(3x) = -5\\4. 3x = -5\\5. x = -1.66$

Drupady [299]4 years ago

5 0

Answer:

it is very simple -5 =(5)(-1)=(x+4)(2x-3).so compare( 5)=(x+4) and (x=1) it can be solved by mind.....(2x^2)+5x-7=0 then

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3 years ago

All 231 students in math club went on a field trip some rode in vans that held 7 people and some rode on buses that held 25 peop

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Answer:

8 vans

7 buses

Step-by-step explanation:

Let there be "b" buses

and "v" vans

Since 7 people is the capacity of vans, the total capacity is

Also, since 25 people is the capacity of 1 bus, the total capacity is

25b

In total 231 people, so we can write our first equation as:

7v + 25b = 231

Now, we know there are 15 vehicles (bus + vans) in total, so we can write our 2nd equation as:

v + b = 15

Now, we solve for v and b. Let's solve the 2nd equation for v and substitute that into 1st and solve for b first:

v + b = 15

v = 15 - b

Now,

$7v + 25b = 231\\7(15-b) + 25b = 231\\105-7b+25b=231\\18b=126\\b=7$

Hence, there are 7 buses

Since 15 vehicles in total, the number of vans is:

15 - 7 = 8 vans

So,

8 vans

7 buses

8 0

4 years ago

Find the value of x so that (-2, 4) is the midpoint between (x, 2) and (-5,3).

QveST [7]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{x}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{-5+x}{2}~~,~~\cfrac{3+2}{2} \right)~~=~~\stackrel{midpoint}{(-2,4)}\implies \begin{cases} \cfrac{-5+x}{2}=-2\\[1em] -5+x=-4\\ \boxed{x=1} \end{cases}$