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Ad libitum [116K]
4 years ago
7

Please find "s" 11 = -6s

Mathematics
2 answers:
Vikki [24]4 years ago
4 0
The answer to this question is -11/6
ddd [48]4 years ago
3 0
Since s is multiplied by -6, divide both sides by -6 to isolate s.

11=-6s
11/-6= -6s/-6
-11/6= s

Final answer: s=-11/6
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Solve the system of equations using subtraction.<br> 3x – 3y = -6<br> 3x + y=10
LUCKY_DIMON [66]

Answer:

(2,4)

Step-by-step explanation:

x=2

y=4

8 0
3 years ago
Hello i need help on this please its for a small quiz i have and we are aloud to use the internet :)
shepuryov [24]

Answer:

Just download air math and take a picture of it a you will get immediate answer.

Step-by-step explanation:

8 0
2 years ago
If y varies directly as x and z, and y=8/3 when x=1 and z=4, find y when x=6 and z=3
Butoxors [25]

8/3 =k(1)(4)

8/3 =4k

k=(8/3)/4

k =2/3


y= 2/3 *(6)(3)

y = 2/3 x 18

y = 12


7 0
3 years ago
You invest $75.00 the first month and $1,000.00 the second month at 3.75% APR. How much interest do you accrue at the end of the
Naddika [18.5K]

Answer

At end of the second month you earned $3.36 as interest.

Step by step explanation

First month investment = $75

Rate of interest = 3.75% APR = 3.75/100 = 0.0375

Monthly interest = 0.0375/12 = 0.003125

At end of the first month interest amount = 0.003125 *75 = 0.234375

= $0.23

Amount after 1st month = 75 + 0.23 = $75.23

Second month invested $1000/

So the principle amount at beginning of the second month = $1000 + $75.23

P = $1075.23

Second month interest = 1075.23*0.003125 = $3.36

Therefore, at end of the second month you earned $3.36 as interest.

Thank you. :)

8 0
4 years ago
Evaluate: tan(-120 degrees).
dem82 [27]
-120° = -2π/3 radians.

Tangent is defined as Opposite/Adjacent or Sine/Cosine in a unit circle. So, if you have memorized the unit circle,

sin(-2π/3) = √3/2
cos(-2π/3) = -1/2

So, tan(-2π/3) would be:
\frac{ \frac{ \sqrt{3} }{2} }{ \frac{-1}{2} } =  \frac{ \sqrt{3} }{2}* -\frac{2}{1}

Simplify, and you get:
-\frac{2 \sqrt{3} }{2}  = - \sqrt{3}

And, so, tan(-2π/3) = -√3
8 0
3 years ago
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