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Eddi Din [679]
3 years ago
12

Assignment

Mathematics
1 answer:
allochka39001 [22]3 years ago
4 0

Answer:

Step-by-step explanation:

kerurity

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Drag the tiles to the correct boxes to complete the pairs.
Alborosie

2⁻³² = (-2²)⁻⁶ • (2⁻⁵)⁻⁴

2⁻⁵ = (2²)² • (2³)⁻³

2⁸ = (-2⁻⁴)⁻² • (2²)⁰

1 = 2⁴ • (2²)⁻²

6 0
3 years ago
3a+a+2a-5a? <br><br><br> Can someone give me the answer please? <br><br> Ty
Shkiper50 [21]

Answer:

a

Step-by-step explanation:

=3a + a + 2a - 5a

=4a - 3a

= a

hope it helps u tate!

5 0
3 years ago
Read 2 more answers
X* square root of 3 =34
disa [49]

Answer:

17.49286

Step-by-step explanation:

Photomath :)

4 0
3 years ago
Read 2 more answers
Pls help i am on a timer
stich3 [128]

Answer:

x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}

Step-by-step explanation:

Given;

x² - 2x - 1 = 0

Solve by completing the square method;

⇒ take the constant to the right hand side of the equation.

x² - 2x = 1

⇒ take half of coefficient of x = ¹/₂ x -2 = -1

⇒ square half of coefficient of x and add it to the both sides of the equation

x^2 +  (-1)^2 = 1 + (-1)^2

(x-1)^2 = 1 + 1\\\\(x-1)^2 = 2\\\\

⇒ take the square root of both sides;

x-1 = +/- \ \ \sqrt{2} \\\\x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}

Therefore, option B is the right solution.

3 0
3 years ago
Surface Area of Cylinder=2πrh+2πr2
Alex

  • Find the surface area when r is 8 inches and h is 8 inches.

\qquad A. 160π in²

\qquad B. 154π in²

\qquad C. 288π in²

\qquad D. 256π in² ☑

We are given –

\qquad ⇢Radius of cylinder , r = 8 inches

\qquad⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }

Now, Substitute given values –

\sf  \twoheadrightarrow  Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 2 \pi \times 8 \times 8 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  =128 \pi + 128\pi

\purple{\bf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 256\pi \: in^2 }

  • Henceforth,Option D is the correct answer.

8 0
2 years ago
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