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shusha [124]
3 years ago
13

James cut out four parallelograms, the dimensions of which are shown below. Parallelogram 1 length: 12 in. width: 15 in. diagona

l: 20 in. Parallelogram 2 length: 16 in. width: 30 in. diagonal: 34 in. Parallelogram 3 length: 20 in. width: 21 in. diagonal: 29 in. Parallelogram 4 length: 18 in. width: 20 in. diagonal: 26 in. James put the parallelograms together so one vertex from each paper exists on a point, as shown in the circle. 4 parallelograms are put together so that one vertex from each paper exists on a point. Which statement explains whether or not the parallelgrams can be put together so each occupies one-quarter of the area of the circle without overlapping any other pieces? Check all that apply. The quadrilaterals can be placed such that each occupies one-quarter of the circle. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 2 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 3 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.
Mathematics
2 answers:
Vlad1618 [11]3 years ago
8 0

Answer:

B and E

Step-by-step explanation:

The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles.

The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.

jok3333 [9.3K]3 years ago
5 0

Answer:

the answer is b and e

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

(0, inf)

Step-by-step explanation:

The average rate of change of a function is related to it's first derivative. When the first derivative is positive, the average rate of change is positive, which means that the function is crescent.

Now, when the first derivative is negative, the average rate of change will be negative too, and the function is going to be decrescent.

In your function.

We have: f'(x) = 2x

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6 0
3 years ago
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Step-by-step explanation:

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Which shows the correct way to evaluate 10 × 4 – (5 – 3) + 2? 10 × 4 – (5 – 3) + 2 10 × 4 – (2 + 2) 10 × 4 – 4 10 × 0 0 10 × 4 –
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Answer:

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Step-by-step explanation:

To solve;

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