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3 years ago

11

Expression equivalent to 17s-10+3(2s+1)?

1 answer:

kiruha [24]3 years ago

6 0

He number of 1s or 0s in binary representation of a number<span>up vote2down votefavoriteWhat is the number of 1s in the binary representation of<span><span>3×512+7×64+5×8+3</span><span>3×512+7×64+5×8+3</span></span>Is there any shortcut for finding the number of <span><span><span>1′</span>s</span><span><span>1′</span>s</span></span> and <span><span><span>0′</span>s</span><span><span>0′</span>s</span></span> in a binary number which has been factored as above?</span>

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a van travels 300 miles on 15 gallons of gas. find how many gallons the van needs to travel 360 miles

nignag [31]

Answer:

18 gallons

Step-by-step explanation:

divide 300 by 15 you 150 or 15 again then add 1 gallon per every twenty miles

thus your answer is 18 gallons of gas

4 0

3 years ago

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How many grams are equal to 5,673 milligrams? Use the placement of the decimal point when dividing by a power of 10 to help you.

Nadusha1986 [10]

Answer:

5.673

Step-by-step explanation:

4 0

3 years ago

If 12g of a radioactive substance are present initially and 8yr later only 6g remain, how much if the substance will be present

Brums [2.3K]

The weight of substance remaining after 13 years is 2.25 g.

Given:

Present weight of substance = 12 g

After 8 years weight remains = 6 gm

Now, weight loss in 8 year will be,

12-6=6 gm

So, weight loss in 1 year will be,

$\dfrac{6}{8} =\dfrac{3}{4}$

Total weight loss in 13 year will be,

$\dfrac{3}{4}\times13=9.75$

The weight of substance remaining after 13 years will be,

$12- 9.75 = 2.25 \;\rm g$

Therefore, the weight of substance remaining after 13 years is 2.25 g.

To know more about radioactive decay, refer to the link:

brainly.com/question/12116123

5 0

3 years ago

You take measurements of the distance traveled by an object that is increasing its speed at a constant rate. The distance travel

Serhud [2]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Given:

$s_1 = 21 \ \ t_1 = 1\\\\s_2 = 59 \ \ t_2 = 2\\\\s_3 = 141 \ \ t_3 = 4$

All points are on the graph including its quadratic function, in order to install their coordinates to values of x and y with the following values:

$y= ax^2 + bx + c\\\\21=a+b+c$ Inserting the coordinates of the first point

$y= ax^2 + bx + c\\\\59 =4a+2b+c$ Inserting the coordinates of the second point

$y= ax^2 + bx + c\\\\141=16a+4b+c$ Inserting the coordinates of the third point

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3 years ago

5. Which statement is true?

sveta [45]

All rectangles are quadrilaterals because a quadrilateral has 4 sides and all rectangles have 4 sides so that one is correct

8 0

3 years ago

Read 2 more answers