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Olegator [25]
3 years ago
14

Please explain how to do

Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
a)\\\\
\cfrac{large~vase}{small~vase}\qquad 3:2\qquad \cfrac{3}{2}\qquad \cfrac{3^3}{2^3}=\cfrac{1080}{x}\implies x=\cfrac{2^3\cdot 1080}{3^3}
\\\\\\
x=320
\\\\\\
b)\\\\
\cfrac{large~vase}{small~vase}\qquad 3:2\qquad \cfrac{3}{2}\qquad \cfrac{3^2}{2^2}=\cfrac{x}{252}\implies \cfrac{3^2\cdot 252}{2^2}=x
\\\\\\
567=x
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Alvin is 7 years younger than Elgas. The sum of their ages is 63. What is Elgas age?
Elden [556K]

Answer:

Elgas is 35.

Step-by-step explanation:

Let's set up an equation.

Alvin is 7 years younger than Elgas.

A = E - 7

The sum of their ages is 63.

A + E = 63

Let's use substitution.

Plug in the first equation of A into the second equation.

A + E = 63

(E - 7) + E = 63

Combine like terms.

2E - 7 = 63

Add 7 to both sides.

2E = 70

Divide both sides by 2.

E = 35

Elgas is 35.

Hope this helps!

6 0
3 years ago
What is the solution to the equation <br><br> 7(3-x)=-7(x+3)-4
marissa [1.9K]

Answer:

No solution

Step-by-step explanation:

21−7x=−7x−21−4

21−7x=−7x−25

21=−25

No solution

4 0
3 years ago
A family is driving from Phoenix to San Francisco. On a map grid, Phoenix is located at (–12, –16), and San Francisco is located
makkiz [27]
The answer is 34.05

The total distance (D) is the sum of three distances (d1, d2, and d3).

The distance formula is d = \sqrt{(x2-x1)^{2} +(y2-y1)^{2}}

Distance 1: Phoenix (–12, –16) to Blythe (–20, –9)<span>:
</span>d1 = \sqrt{(-20-(-12))^{2} +(-9-(-16))^{2}} =\sqrt{(-20+12)^{2} +(-9+16)^{2}} \\ =\sqrt{(-8)^{2} +(7)^{2}}= \sqrt{64+49} = \sqrt{113}= 10.63

Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
d2 = \sqrt{(-33-(-20))^{2} +(-4-(-9))^{2}} =\sqrt{(-33+20)^{2} +(-4+9)^{2}} \\ =\sqrt{(-13)^{2} +(5)^{2}}= \sqrt{169+25} = \sqrt{194}= 13.93

Distance 3: Los Angeles (–33, –4) to <span>San Francisco (–36, 5)
</span>d3 = \sqrt{(-36-(-33))^{2} +(5-(-4))^{2}} =\sqrt{(-36+33)^{2} +(5+4)^{2}} \\ =\sqrt{(-3)^{2} +(9)^{2}}= \sqrt{9+81} = \sqrt{90}= 9.49
<span>
D = d1 + d2 + d3 = 10.63 + 13.93 + 9.49 = 34.05</span>
3 0
3 years ago
Tyler earned $364.80 at his job when he worked for 16 hours. How much money did he earn each hour?
oksano4ka [1.4K]

Answer: $22.80/hour

Step-by-step explanation: 364.80 : 16 = 22.80

5 0
3 years ago
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

5 0
3 years ago
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