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zubka84 [21]
4 years ago
15

Is Alexis drove her car for three hours and drove 150 miles and then drove her car for 350 miles in four hours what is her avera

ge speed for the journey

Mathematics
1 answer:
sleet_krkn [62]4 years ago
4 0
Alexis's average speed was 68.74 miles per hour

Hope this helps!
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The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c
Slav-nsk [51]

\text{Answer} : \text{The expected value of a t-shirt is \$31.}

Explanation:

Since we have given that

The prices of three t-shirts styles  i.e $24, $30, $36 with their probability is given by

\frac{1}{6}, \frac{1}{2},\frac{1}{3}

As we know that,

E(X)= \sum_{1}^{3}x_iP(x_i)

\text{where} x_i \text{ is the prices of t- shirts styles}

Now,

x_1= \$24 , x_2=\$30 , x_3=$36

and

P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}

So,

E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31

So, the expected value of a t-shirt = $31.

4 0
3 years ago
Approximately how many times bigger was the 1908 siberian asteroid than the diameter of the chelyabinsk asteroid
elena-14-01-66 [18.8K]

1908 Siberian Asteroid is known to be 130 feet/ 18 meters in diameter while on the other hand Chelyabinsk Asteroid is known to be 59 feet/40 meters in diameter. To find how many times Siberian Asteroid is bigger than Chelyabinsk Asteroid we just have to divide Siberian by Chelyabinsk here we get:

10/59=2.2 = 1908 Siberian Asteroid is 2.2 times bigger than Chelyabinsk Asteroid.

 

4 0
3 years ago
Two rockets, A and B, are shot from two different launch pads. The path of rocket A can be represented by the quadratic function
oksano4ka [1.4K]
<span>A(t) = −(t − 8)2 + 535
You would like to find the maximum of this function:</span> −(t − 8)^2<span>This part is always negative or zero as a number squared cannot be negative and you multiply by -1:  Thus the maximum of this part MAX:</span>−(t − 8)^2=0  
<span>The max will be when t=8 and its value is 535

</span>
4 0
3 years ago
A cylindrical container with a radius of 5 cm and a height of 14 cm is completely filled with liquid. Some of the liquid from th
Flura [38]

Answer:

The remaining liquid has a volume of 345.4 cm³.

Step-by-step explanation:

To solve this question we first need to calculate the volume of each container.

Cylindrical:

Volume = h*pi*r² = 14*3.14*(5)² = 1099 cm³

Cone:

Volume = (1/3)*h*pi*r² = (1/3)*20*3.14*(6)² = 753.6 cm³

Since the liquid from the cylinder was transfered to the cone until the latter was full, then what remains in the cylinder is it's original volume minus the cone volume. So we have:

remaining liquid = 1099 - 753.6 = 345.4 cm³

4 0
3 years ago
Please help meeeeee!!!!
ser-zykov [4K]
I think the answer is B y= 3x-7
8 0
3 years ago
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