find the sum of the areas under the standard normal curve to the left of z=1.25 and to the rightof z=1.25
1 answer:
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<u>Answer:</u>
x = & 3
<u>Step-by-step explanation:</u>
=
Cross multiply:
=
⇒ (8x)(7x) = (5x+3)(10x-2)
Simplify both sides:
(8x)(7x) = (5x+3)(10x-2) ⇒ 56x² = 50x²+20x-6
Set equation equal to 0:
56x² = 50x²+20x-6 ⇒ 0 = -6x²+20x-6
Factor the trinomial:
0 = -6x²+20x-6 = (-6x+2)(x-3)
Solve for X:
-6x+2 = 0
-6x = -2
x = ;
x-3 = 0
x = 3;
x = , 3