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3 years ago

Between which two numbers will you find 6.431?

Mathematics

2 answers:

eimsori [14]3 years ago

7 0

The answer is: D.) 6.4 and 6.5

AfilCa [17]3 years ago

5 0

Answer:

6.4 and 6.5

Step-by-step explanation:

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Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

4 0

3 years ago

Find the missing dimension of the triangle<br><br>

Stels [109]

Answer:

b=7

Step-by-step explanation:

A=bh/2

28=8b/2

56=8b

b=7

8 0

3 years ago

What expression is equivalent to 3/5(3y+15)

choli [55]

\left[y \right] = \left[ -5\right][y]=[−5] totally answer

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3 years ago

three friends earned more then $200 washing cars. they paid their parents $28 for supplies and divides the rest of money equally

Allushta [10]

X is each friend
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3x > 172
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3 years ago

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3241004551 [841]

-8/12

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3 years ago