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madam [21]
3 years ago
12

Fill in the other coordinate for the line 2x−5y=11 (2, )

Mathematics
2 answers:
DerKrebs [107]3 years ago
8 0
Well what you do is move the 2x over to the other side to make y=mx+b. It should look like this: -5y=-2x+11. Then you replace the x with 2,it should now look like this: -5y=-2(2)+11. Then you simplify and get this: -5y= 7. Then you divide -5 by both sides and get: y= 1.4 or 1 2/5. Hope that helped! If this is wrong to you double check the question you wrote.
Eduardwww [97]3 years ago
8 0
Given the equation 2x - 5y = 11 and x = 2, plug the 2 in for x and solve for y.
2(2) - 5y = 11
4 - 5y = 11
subtract 4 from both sides
-5y = 7
divide both sides by -5
y = -7/5
(2, -1.4)
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dolphi86 [110]

Answer:

\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

A_\triangle=\dfrac{bh}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We need a length of a height.

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=5,\ leg=h,\ hypotenuse=20

Substitute:

5^2+h^2=20^2

25+h^2=400             <em>subtract 25 from both sides</em>

h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm

Calculate the area:

A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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