For there to be a region bounded by the two parabolas, you first need to find some conditions on

. The two parabolas must intersect each other twice, so you need two solutions to

You have

which means you only need to require that

. With that, the area of any such bounded region would be given by the integral

since

for all

. Now,

by symmetry across the y-axis. Integrating yields

![=4\left[c^2x-\dfrac{16}3x^3\right]_{x=0}^{x=|c|/4}](https://tex.z-dn.net/?f=%3D4%5Cleft%5Bc%5E2x-%5Cdfrac%7B16%7D3x%5E3%5Cright%5D_%7Bx%3D0%7D%5E%7Bx%3D%7Cc%7C%2F4%7D)



Since

, you have

.
First off, you have to make 65 % into an actual number, which is 0.65 (every time you want to convert percentages into numbers, you have to divide that by 100)
Now
0.65 * 8700 = 5655
Answer: 5655
10/3 = 1 1/5 so that’s the answer
C because that’s the equations to find the proportion;)
Please refer the photograph for the answer
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