F(x)=(x−8)(x−2)
y=(x−5)2−9
(Pretend the 2 is an exponent)
Use the vertex form, y=a(x−h)2+ky=a(x-2+k, to determine the values of a,h, and k.
a=1
h=5
k=-9
Find the vertex (h, k).
(5, -9)
2 x 7 x 7 or in exponential form, 2 x 7². 98 turns into 2 times 49, then 49 turns into 7 times 7.
Answer:
bx=-3
Step-by-step explanation:
-2(bx-5)=16
Use distributive property.
-2bx+10=16
Now, subtract 10 from both sides.
-2bx=6
Divide -2 from both sides.
bx=-3
Hope this helps!
If not, I am sorry.
Answer:
6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- |Absolute Value| - makes any number positive
Step-by-step explanation:
<u>Step 1: Define</u>
|bc|
a = 5
b = -3
c = -2
<u>Step 2: Evaluate</u>
- Substitute: |-3 · -2|
- Multiply: |6|
- Evaluate: 6
Step-by-step explanation:
In this problem, all we have to do is replace x and y with the values we've been given.
It can be helpful to think of 3x as 3 * x (which is the same exact thing), so I'll write it out that way.
3*x - 4*y
(replace)
3*4 - 4*3
(multiply (doing this step first because of PEMDAS))
12 - 12
(subtract)
0
Answer:
0
