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dexar [7]
3 years ago
8

Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

Mathematics
2 answers:
trasher [3.6K]3 years ago
6 0

Answer by JKismyhusbandbae: 12

Solve the equation for a

Work: (listed in picture)


9966 [12]3 years ago
3 0

Simplify the equation:

(a + -5) + a = 19

Reorder the terms:

(-5 + a) + a = 19

Remove the parenthesis around (-5 + a) :

-5 + a + a = 19

Combine like terms:

a + a = 2a

-5 + 2a = 19

Final equation:

-5 + 2a = 19

To solve for variable A:

You have to move all terms containing A to the left, all the other terms to the right.

Add '5' to each side of the equation.

-5 + 5 + 2a = 19 + 5

Combine like terms again:

-5 + 5 = 0

0 + 2a = 19 + 5

2a = 19 + 5

Combine like terms:

19 + 5 = 24

2a = 24

Finally divide each side by '2':

a = 12

Simplify:

a = 12

Answer: A=12

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Witch expression represents a number 5 times the difference of 6 and 2
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2 years ago
5<br> 0 = - in<br> =<br> in quadrant II<br> Given cos =<br> Find sin<br> 3
____ [38]

Answer:

sinΘ = \frac{2}{3}

Step-by-step explanation:

using the identity

sin²x + cos²x = 1  ( subtract cos²x from both sides )

sin²x = 1 - cos²x ( take square root of both sides )

sinx = ± \sqrt{1-cos^2x}

given

cosΘ = - \frac{\sqrt{5} }{3} , then

sinΘ = ± \sqrt{1-(-\frac{\sqrt{5} }{3})^2 }

        = ± \sqrt{1-\frac{5}{9} }

        = ± \sqrt{\frac{4}{9} }

        = ± \frac{2}{3}

since Θ is in quadrant II where sinΘ > 0 , then

sinΘ = \frac{2}{3}

7 0
2 years ago
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