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Alika [10]
4 years ago
5

16 centimeters to 44.2 centimeters

Mathematics
1 answer:
Phoenix [80]4 years ago
7 0

Problem work:

y1 =16
y2 = 44.2


( 44.2-16/16) x 100

(1.7625) x 100

So the percent increase (percent change) will be 176.25%

hope this helps

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What is the area, in square centimeters, of the trapezoid below? 18.2 cm 9.2 cm 8.3 cm​
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5 0
3 years ago
Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
3 years ago
Read 2 more answers
How do you find the area of this (it is not 12 or 18) The First answer gets brainliest
bija089 [108]

Answer:

<em><u>ok the area of a trapezoid is 48 </u></em>

a+b divided by two multiplied by height  

Step-by-step explanation:

each square equals 2 so you count by twos instead of ones..

the height is 8   the base is 8 and the top is 4 so

4+8/2=6

6*8=48

6 0
4 years ago
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