<u>Answer</u>
5) b-c
6) a-b and
e-f
7) f-g
9) a-b = 0 m/s
c-d = 0.6667 m/s
e-f = 0 m/s
f-g = -3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
<u>Explanation</u>
Answer
5) b-c
In the section b-c the cart is accelerating because the slope of the graph is changing. The gradient that represent velocity is increasing.
6) a-b and e-f
At this sections the distance is not changing at all. This can only mean that the cart is not moving. It is at rest.
7) f-g
At this section the slope is negative meaning the cart is moving back to where it came from.
9) a-b = 0 m/s
At a-b the cart is not moving. So the velocity is zero.
<u> c-d = 0.66667 m/s</u>
Velocity = distance / time
=(50-40)/(40-25)
= 10/15
= 0.6667 m/s
<u> e-f = 0 m/s</u>
At e-f the cart is not moving. So the velocity is zero.
<u> f-g = -3 m/s</u>
Velocity = distance / time
= (60-30)/(65-75)
= 30/-10
= - 3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
